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scZoUnD [109]
3 years ago
13

Which of these substances has a definite volume but not a definite

Chemistry
2 answers:
vovikov84 [41]3 years ago
8 0
I think answer should be b. Please give me brainlest I hope this helps let me know if it’s correct or not okay thanks
Yuki888 [10]3 years ago
6 0
The answer would be b
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How many grams of carbon are contained in 2.25 g of potassium carbonate, K2CO3
romanna [79]

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

<h3>Molecular mass of potassium carbonate</h3>

The molecular mass of potassium carbonate, K₂CO₃ is calculated as follows;

M = K₂CO₃

M = (39 x 2) + (12) + (16 x 3)

M = 138 g

mass of carbon in potassium carbonate, K₂CO₃ is = 12 g

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is calculated as follows;

138 g ------------ 12 g of carbon

2.25 g ------------ ?

= (2.25 x 12) / 138

= 0.196 g

Thus, the mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

Learn more about potassium carbonate here: brainly.com/question/27514966

#SPJ1

5 0
2 years ago
What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?
tamaranim1 [39]
<h2>Answer:AlF_{3} </h2>

Explanation:

The chemical equation of the reaction that occurs when AlF_{3} reacts with O_{2} is

4AlF_{3}+3O_{2}→2Al_{2}O_{3}+6F_{2}

4 moles of AlF_{3} requires 3 moles of O_{2}.

1 mole of AlF_{3} requires \frac{3}{4} moles of O_{2}.

Given that we have 9 moles of AlF_{3}.

9 moles of AlF_{3} requires \frac{3}{4}\times 9=6.75 moles of O_{2}.

But we have 12 moles of O_{2}.

So,AlF_{3}  will be consumed first.

So,AlF_{3}  is the limiting reagent.

3 0
3 years ago
How many moles of HNO3 are present in 450 g of HNO3?
iVinArrow [24]
Since there are 63.01284 grams to one mole of HNO3, then 12.5 moles would be in 450 grams of it.
6 0
3 years ago
During a reaction, the enthalpy of formation of an intermediate is -286
Darina [25.2K]

Answer:

O A. -572 kJ

Explanation:

3 0
2 years ago
Using molecular orbital theory, explain why the removal of one electron in O2 strengthens bonding, while the removal of one elec
Nuetrik [128]
First you have a knowledge of bond order which is
 B.O=(no. of electrons in bonding orbital - no. of electrons in non-bonding orbital)÷2  
Note:
bond strength is directly proportional to bond order.
For oxygen:
B.O=(6-2)/2= 2; after the removal of two electrons(removal occur from non-bonding orbital)
B.O=(6-0)/2= 3 (As B.O increased bond strength increased)
For Nitrogen:
B.O=(6-0)/2= 3; after the removal of two electrons(removal occur from bonding orbital)
B.O=(4-0)/2= 2 (As B.O decreased bond strength decreased)

6 0
3 years ago
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