Which of these substances has a definite volume but not a definite

Chemistry

2 answers:

vovikov84 [41]2 years ago

8 0

I think answer should be b. Please give me brainlest I hope this helps let me know if it’s correct or not okay thanks

Yuki888 [10]2 years ago

6 0

The answer would be b

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How many electrons would Boron with a +2 charge have?

irina [24]

5 electrons

Boron atomic number 5 has five electrons in its ground state.

Commonly Boron will lose 3 electrons leaving 2 electrons in its most common ionic form.

Explanation:

The atomic number gives the number of protons. Protons which have a positive charge are balanced by an equal number of electrons in a neutral atom.

Boron number 5 has five protons and therefore as a neutral atom also has five electrons.

Boron has an electron configuration of

1s22s22p1

The most stable electron configuration for Boron is

1s2

+ 3 charges. By losing three electrons Boron can achieve the stable electron structure of Helium

Brainliest? :D

4 0

3 years ago

How many milliliters of an aqueous solution of 0.164 M chromium(II) bromide is needed to obtain 2.26 grams of the salt? ____mL

Mila [183]

The answer would possible 0.25ml

7 0

2 years ago

Determine the volume occupied by 0.352 mole of a gas at 25⁰C if the pressure is 81.8 kPa.

lions [1.4K]

Data:
p (pressure) = 81.8 kPa = 81.8*10³ Pa ≈ 8.07 atm
v (volume) = ? (in L)
n (number of mols) = 0.352 mol
R (Gas constant) = 0.082 (atm*L/mol*K)
T (temperature) = 25ºC converting to Kelvin, we have:
TK = TC + 273 → TK = 25 + 273 → TK = 298

Formula:
$p*V =n*R*T$

Solving:
$p*V =n*R*T$
$8.07*V = 0.352*0.082*298$
$8.07V \approx 8.60$
$V \approx \frac{8.60}{8.07}$
$\boxed{\boxed{V \approx 1.06\:L}}$

7 0

3 years ago

If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

AVprozaik [17]

Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
------------------------------------------------------------------------------------------------------
Find pOH
1 + pOH = 14

pOH = 13
------------------------------------------------------------------------------------------------------
Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is $[OH-] = 1 * 10^{-13} mol/L$

Hope this helps!

3 0

3 years ago

50 ml of 0.2 M acetic acid is shaken with 10 g activated charcoal. The concentration of acetic acid is reduced to 0.5 times the

Olegator [25]

Answer:

$0.03 g_{acid}/g_{charcoal}$