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Brut [27]
3 years ago
6

Radio astronomers detect electromagnetic radiation at a frequency of 42MHz from an interstellar gas cloud. If the radiation resu

lts from electrons spiraling in a magnetic field, What is the magnetic field strength inside the gas cloud?
Physics
1 answer:
ExtremeBDS [4]3 years ago
5 0

Answer:

Explanation:

The electrons will also spiral with frequency of 42 x 10⁶

n = 42 x 10⁶

For circular motion of electron

= Bqv = m ω² r ( centripetal force )

v / r = m ω² / Bq

= 4π² n² m / Bq

T =  2πr / v

1 / n  = 2πr / v

r / v = 1 / 2π n

2π n = ω²m / Bq

ω = ω² m/ Bq

B =  ω m / q

B = 2π nm / q

= 2  x 3.14 x 42 x 10⁶ x 9.1 x 10⁻³¹ / 1.6 x 10⁻¹⁹

= 15 x 10⁻⁴  T

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A -3.00 nc point charge is at the origin, and a second -5.50 nc point charge is on the x-axis at x = 0.800 m. find the electric
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The electric field produced by a single-point charge is given by

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To find the electric field at x=0.200 m, we need to find the electric field produced by each charge at that point, and then find their resultant.


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2) The second charge is q=-5.50 nC=-5.5 \cdot 10^{-9}C and it is located at x=0.800 m, so its distance from the point is

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3) The total electric field at x=0.200 m will be given by the difference between the two fields (because they are in opposite directions). Taking the x-positive direction as positive direction, we have

E=E_2 -E_1 =137.5 N/C/C-675 N/C=-537.5 N/C

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