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garri49 [273]
3 years ago
7

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist headi

ng north is riding 5 km/hour faster than the bicyclist heading south. At 10:45, they are 47.25 km apart. Find the two bicyclists’ rates (speed/velocity).
Physics
2 answers:
guajiro [1.7K]3 years ago
5 0

Answer:

northbound bicyclist = 16 km/h; southbound bicyclist = 11 km/h

<em>Hope this helps</em>

<em>-Amelia The Unknown</em>

notka56 [123]3 years ago
3 0
Between 9:00 am and 10:45 am, there have been 1 hour and 45 minutes or 1.75 hours have passed. Let x be the speed of the slower cyclist and x+ 5 be the rate of the second cyclist. The given situation is best represented through the equation below,
                                 x(1.75) + (x + 5)(1.75) = 47.25 km
The value of x from the equation is 11. Thus, the two bicyclists' rates are 11 km/h and 16 km/h. 
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A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N
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