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3 years ago

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At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist headi

ng north is riding 5 km/hour faster than the bicyclist heading south. At 10:45, they are 47.25 km apart. Find the two bicyclists’ rates (speed/velocity).

2 answers:

guajiro [1.7K]3 years ago

5 0

Answer:

northbound bicyclist = 16 km/h; southbound bicyclist = 11 km/h

<em>Hope this helps</em>

<em>-Amelia The Unknown</em>

notka56 [123]3 years ago

3 0

Between 9:00 am and 10:45 am, there have been 1 hour and 45 minutes or 1.75 hours have passed. Let x be the speed of the slower cyclist and x+ 5 be the rate of the second cyclist. The given situation is best represented through the equation below,
x(1.75) + (x + 5)(1.75) = 47.25 km
The value of x from the equation is 11. Thus, the two bicyclists' rates are 11 km/h and 16 km/h.

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Answer:

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