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Nadya [2.5K]
3 years ago
12

PLEASE HELP FIRST GETS BRAINLIEST

Chemistry
1 answer:
vazorg [7]3 years ago
4 0

Answer: 1010

Explanation:

Look at the chart

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For the reaction H₂O(g) + Cl₂O(g) → 2HClO(g), you know ΔS°rxn and S° of HClO(g) and of H₂O(g). Write an expression that can be u
expeople1 [14]

The expression for  S°(Cl2O)(g) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

Given ,

The balanced chemical equation is ,

H2O (g) + Cl2O (g) → 2HClO (g)

The general standard entropy of the reaction is given by ,

ΔS°rxn = sum of the S°(Product ) - sum of the S°(reactants )

ΔS°rxn = ΣmS°products  -  ΣnS°reactants

where , m and n are the stoichiometry coefficients of each product and reactants .

Thus , the standard entropy of the given reaction is given by ,

ΔS°rxn = 2×S° (HClO)(g)  - [ S°(H2O)(g) + S°(Cl2O)(g) ]

ΔS°rxn = 2×S° (HClO)(g) - S°(H2O)(g) - S°(Cl2O)(g)

Thus the S°(Cl2O) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

Hence the expression for the standard entropy of Cl2O (g) is given by ,

S°(Cl2O)(g) = 2×S°(HClO)(g) - S°(H2O)(g) - ΔS°rxn

<h3>What is a balance chemical reaction ?</h3>

A balanced chemical reaction is a type of reaction which include the reactants and products in same amount i.e. the no of mole on both side of the reaction is remains same or balanced .

Learn more about chemical reaction here :

brainly.com/question/1893305

#SPJ4

6 0
2 years ago
When is an atom least likely to react
KonstantinChe [14]
When the atom is stable
4 0
3 years ago
Read 2 more answers
Please help me I have not gone over this in like 8 months and can not remember how to do it
Leona [35]

Answer:

91%

Explanation:

Since you are just trying to find the yield, take the moles of the substance from the products and divide it by the mol value of the reactants. Multiply by 100 to find percentage

0.45 ÷ 0.41 = 0.91111...

91%

4 0
3 years ago
Which of the following reactions have a positive ΔSrxn? Check all that apply.
PolarNik [594]

Answer:

The reactions that have a <em>positive ΔS rxn </em>are the first and the fourth choices:

  • <em>2A(g) + B(s) → 3C(g)</em>

  • <em>2A(g) + 2B(g) → 5C(g)</em>

Explanation:

<em>ΔS rxn </em>is the change of entropy of the chemical reaction.

ΔS rxn = S after reaction - S before reaction.

Therefore, a positive ΔS rxn  means that the entropy after the reaction is greater than the entropy before the reaction.

You may use some assumptions to predict whether a reaction will lead an increase or decrease of the entropy.

First, assume that all the non-shown conditions, such as temperature and pressure, are constant.

Under that assumption, and from the meaning of entropy as a measure of the disorder or randomness of a system you can predict the sign of the change of entropy.

  • <em><u>2A(g) + B(s) → 3C(g)</u></em>

        1)  The solid compounds, B(s) in this case, are very ordered and so they have low entropy.

        2) Gas molecules are highly disordered (scattered), and the greater the number of molecules of the gas the larger the entropy, S).

Hence, since the product side shows 3 gas molecules and the reactant side shows 2 gas molecules and 1 solid molecule, you predict that the products have a larger entropy than the reactants, meaning an increase in entropy: <em>ΔS rxn is positive.</em>

  • <em><u>2A(g) + B(g) → C(g)</u></em>

Using the same reasoning, 3 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>A(g) + B(g) → C(g)</em></u>

Again, 2 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>2A(g) + 2B(g) → 5C(g)</em></u>

With the same reasoing, 5 molecules in the product side, lets you predict that will have more entropy than 4 molecules in the reactant side, and, the entropy will increase: <em>ΔS rxn is positive.</em>

6 0
4 years ago
If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro
In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.  

Molality=

\frac{Number of moles of solute}{Mass of solvent in kg}

Number of moles of solute, n=  

\frac{Given mass of the substance}{Molar mass of the substance}

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,  

n= \frac{0.2 }{123.06}

Number of moles of nitrobenzene, n= 0.0016  mol

Mass of 10.9 g of naphthalene in kg=0.0109  

Molality= \frac{0.0016}{0.0109 }

Molality= 0.146 m

7 0
3 years ago
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