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Tema [17]
3 years ago
9

A plane on the ground will weigh

Chemistry
1 answer:
sergejj [24]3 years ago
5 0

Answer:

The weight of the plane is  (mass) x (acceleration of gravity).

Neither of these changes when the plane rises from the ground.

Its weight on the ground is equal to (the same as) its weight in the air.

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Convert the temperature of the coldest area in freezer, -10 fahrenheit, to degrees celsius and kelvin.
babunello [35]

Answer : The temperature in degree Celsius and Kelvin are, -23.33^oF\text{ and }249.82K

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

where,

^oF = temperature in Fahrenheit

^oC = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273.15+^oC

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in Fahrenheit is, -10

Now we have to determine the temperature in degree Celsius.

^oC=(^oF-32)\times \frac{5}{9}

^oC=(-10^oF-32)\times \frac{5}{9}

^oC=-23.33

Now we have to determine the temperature in Kelvin.

K=273.15+^oC

K=273.15+(-23.33^oC)

K=249.82

Therefore, the temperature in degree Celsius and Kelvin are, -23.33^oF\text{ and }249.82K

5 0
3 years ago
Read 2 more answers
This chart shows the global temperature anomaly (the difference of the expected temperature and the actual temperature) over a s
Vaselesa [24]
I think a and c. Let me know if I am wrong.
3 0
3 years ago
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The reaction N2 + H2 —-> NH3, if 2.00 grams of hydrogen reacts: how many grams of ammonia are
Anon25 [30]

Answer:

mass NH3 = 11.264 g

mass N2 = 9.264 g

Explanation:

balanced reaction:

  • N2 + 3H2 → 2NH3

∴ mass H2 = 2.00 g

∴ molar mass H2 = 2.016 g/mol

∴ molar mass N2 = 28.0134 g/mol

∴ molar mass NH3 = 17.031 g/mol

⇒ mol H2 = (2.00 g)*(mol/2.016 g) = 0.992 mol

⇒ mol NH3 = (0.992 mol H2)*(2 mol NH3/3 mol H2) = 0.6614 mol

⇒ mass NH3 = (0.6614 mol)*(17.031 g/mol) = 11.264 g

⇒ mol N2 = (0.6614 mol NH3)*(mol N2/2 mol NH3) = 0.3307 mol

⇒ mass N2 = (0.3307 mol)*(28.0134 g/mol) = 9.264 g

3 0
3 years ago
students used a balance and a graduated cylinder to collect the data shown in table 7. calculate the density of the sample. if t
Licemer1 [7]

Answer:

              Percentage error  =  1.88 %

Solution:

Data Given:

                 Mass of Sample  =  20.46 g

                 Volume of Sample  =  43.0 mL - 40.0 mL  =  3.0 mL

Formula Used:

                 Density  =  Mass / Volume

Putting values,

                 Density  =  20.46 g /  3.0 mL

                 Density  =  6.82 g.mL⁻¹

Percentage Error:

                 Experimental Value  =  6.82 g.mL⁻¹

                 Accepted Value  =  6.95 g.mL⁻¹

                 = 6.82 g.mL⁻¹ / 6.95 g.mL⁻¹ × 100  =  98.12 %

                 Percentage Error  =  100 % - 98.12 %

                Percentage error  =  1.88 %

3 0
3 years ago
PLS ANSWER ASAP
Kazeer [188]
The answer is c this is the answer
7 0
3 years ago
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