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2 years ago

Help me out here, I'll give brainlist for explanation.

Mathematics

1 answer:

LenaWriter [7]2 years ago

5 0

Answer:

See below.

Step-by-step explanation:

This is focusing on the order of operations.

PEMDAS = Parenthesis, exponents, multiplication, division, addition, subtraction.

40 ÷ [(18 - 9) - (13 - 12)]

40 ÷ [9 - 1]

40 ÷ 8

[(13 - 9) · 3] + [(14 - 8) · 2]

[4 · 3] + [6 · 2]

12 + 12

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836.45 write in words

Sindrei [870]

Answer: $Eight\ hundred\ thirty-six\ and\ forty-five\ hundredths$

Step-by-step explanation:

The exercise provides you the following decimal number:

$836.45$

In order to write this decimal number in words, you need to follow these steps:

1. Write the digits to the left of the decimal point as a Whole number. This is:

$Eight\ hundred\ thirty-six$

2. The decimal point is written in words as "and".

3. Write the digits to the right of the decimal point as a Whole number and then write the place name of the last digit located on the right of the decimal point. Then, this is:

$Forty-five\ hundredths$

Therefore, $836.45$ in words is:

$Eight\ hundred\ thirty-six\ and\ forty-five\ hundredths$

5 0

3 years ago

What is the solution to the inequality x/9+7greaterthanequalto10

REY [17]

Answer:

i will try to get it for u

Step-by-step explanation:

6 0

3 years ago

A football is 64 metres wide and 118 metres long. what is its perimeter?

ratelena [41]

I guess you're asking the football court?? cuz a football is sphere shape.
for a rectangular shape just add the width and length together then mmultiply it by 2.
so
(64+118)x2
= 364 m2

7 0

2 years ago

1 less than the square of a number.

julsineya [31]

Answer: 1 is not a perfect square. 3 is the only prime number one less than a square.

7 0

2 years ago

Please help? I’m super lost...

babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function. Watch and see.

a. $sin2\theta =-\frac{\sqrt{3} }{2}$

Take the inverse sin of both sides. When you do that, you are left with just 2theta on the left. That's why you do this.

$sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )$

This simplifies to

$2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )$

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2. Those are:

$2\theta =\frac{5\pi }{6}$ and

$2\theta=\frac{7\pi }{6}$

Divide both sides by 2 in both of those equations to get that values of theta are:

$\theta=\frac{5\pi }{12},\frac{7\pi }{12}$

b. $tan(7a)=1$

Take the inverse tangent of both sides:

$tan^{-1}(tan(7a))=tan^{-1}(1)$

Taking the inverse tangent of the tangent on the left leaves us with just 7a. This simplifies to

$7a=tan^{-1}(1)$

We look to the unit circle to find which values of <em>a</em> give us a tangent of 1. They are:

$7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}$

Dibide each of those equations by 7 to find that the values of alpha are:

$\alpha =\frac{5\pi}{28},\frac{\pi}{28}$

c. $cos(3\beta)=\frac{1}{2}$

Take the inverse cosine of each side. The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems. That simplifies to:

$3\beta=cos^{-1}(\frac{1}{2})$