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Zanzabum
4 years ago
12

Which planets are in the habitable zone? ​

Physics
1 answer:
Vanyuwa [196]4 years ago
6 0

planets

Explanation:

  1. kelper-174d
  2. kelper-443 b
  3. Flies 876 c
  4. 16 Cygnus Bb
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How long does it take a rocket traveling at a constant velocity of 100 m/s to climb from 200m to 1200m
neonofarm [45]

Answer:

10 seconds

Explanation:

you multiply 100 by 10 in order to get 1000m

you add 200m to 1000m to get to the maximum of 1200m

since you travel at 100 per second, it took 10 seconds

7 0
3 years ago
How many seconds did it take (after starting his descent) for the worker to hit the ground? Answer in units of s.
elena-14-01-66 [18.8K]

Answer:

This question is incomplete

Explanation:

The question is incomplete. However, to determine the time (in seconds) it took a worker to hit the ground from an elevated point. The speed the worker was coming with to the ground and the distance between the elevated point and the ground will have to be considered. Thus the formula to be used here will be

Speed (in meter per second) = distance (in meters) ÷ time (in seconds)

time (in seconds) = distance (in meters) ÷ speed (in meter per seconds)

6 0
3 years ago
How many significant figures does 0.09164500561 have?
kolbaska11 [484]

Answer:

10 Sig Figs

Explanation:

Just start counting at the first non zero after the decimal so in this case the nine, and count all of the numbers including zeros after that.

7 0
4 years ago
Light travels 3,00,000km/s. ls it right velocity or speed?​
MrRa [10]

Answer:

speed

Explanation:

because speed is fast

6 0
4 years ago
Read 2 more answers
A mass of 4kg suspended by a light string 2m long and at rest is projected horizontally with a velocity of 1.5 m/s. find the ang
Dafna11 [192]

Answer:

19.5°

Explanation:

The energy of the mass must be conserved. The energy is given by:

1) E=\frac{1}{2}mv^2+mgh

where m is the mass, v is the velocity and h is the hight of the mass.

Let the height at the lowest point of the be h=0, the energy of the mass will be:

2) E=\frac{1}{2}mv^2

The energy when the mass comes to a stop will be:

3) E=mgh

Setting equations 2 and 3 equal and solving for height h will give:

4) h=\frac{v^2}{2g}

The angle ∅ of the string with the vertical with the mass at the highest point will be given by:

5) cos\phi=\frac{l-h}{l}

where l is the lenght of the string.

Combining equations 4 and 5 and solving for ∅:

6) \phi={cos}^{-1}(\frac{l-h}{l})={cos}^{-1}(1-\frac{h}{l})={cos}^{-1}(1-\frac{v^2}{2gl})

8 0
4 years ago
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