Answer:
C₆H₁₂O₆ < NaCl ≈ CH₃OH < MgCl₂
Step-by-step explanation:
The formula for <em>osmotic pressure</em> (Π) is
Π = icRT
If T is constant,
Π = kic
<em>C₆H₁₂O₆:
</em>
Π = k × 1 × 1 = k
<em>MgCl₂:
</em>
Π = k × 3 × 1 = 3k
<em>CH₃OH:
</em>
Π = k × 1 × 2 = 2k
<em>NaCl:
</em>
Π = k × 2 × 1 = 2k
The order of osmotic pressures is
C₆H₁₂O₆ < NaCl ≈ CH₃OH < MgCl₂
Answer:
Total pressure = 22.15 atm
Explanation:
Given data:
Total pressure = ?
Volume of container = 7.85 L
Number of moles of N₂ = 4.45 mol
Number of moles of O₂ = 2.45 mol
Temperature = 307 K
Solution:
Pressure of N₂:
PV = nRT
P = nRT/V
P = 4.45 mol ×0.0821 atm.L/mol.K ×307K / 7.85L
P = 112.16 atm.L/7.85 L
P = 14.28 atm
Pressure of O₂:
PV = nRT
P = nRT/V
P = 2.45 mol ×0.0821 atm.L/mol.K ×307K / 7.85L
P = 61.75 atm.L/7.85 L
P = 7.87 atm
Total pressure = P(N₂) + P(O₂)
Total pressure = P( 14.28 atm) + P( 7.87 atm)
Total pressure = 22.15 atm
Answer:
but-1-yne, it's iupac name of this molecule
formula: C4H6 ✌️:)
HCH bond angle is ~110 degrees.
