Answer:
E =230.4 MJ
Explanation:
As 1 mole of electron = 6X 10^23 particles.
charge of an electron is 1.6 X 10 ^-19 C
Finding Charge:
(6X10^23 ) (2.7)(1.6X10^-19 C)
i.e. 192 K C
now to find the energy released from electrons
V=E/q
E=V X q
i.e E = 120 V X 192 K C
E =230.4 MJ
Answer:
The magnitude of the magnetic force this particle experiences is 
.
Explanation:
Given that,
Velocity v= (3i-5j+k) m/s
Magnetic field B=(i+2j-k) T
We need to calculate the value 
We need to calculate the magnitude of the magnetic force this particle experiences
Using formula of magnetic force
Put the value into the formula
Hence, The magnitude of the magnetic force this particle experiences is .
The purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.
<h3>What is the importance of movement of the scapula during arm elevation?</h3>
The scapula is an important bone which is found in the shoulder and back region of the body.
The scapula enables and increases the range of motion of the arm with its motions.
During arm elevation, the scapula undergoes an upward rotational motion.
Therefore, the purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.
Learn more about scapula motion at: brainly.com/question/5133017
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