Sphere A travels a horizontal distance of (10 m/s) <em>t</em> after time <em>t</em>, while sphere B travels a distance of (5 m/s) <em>t</em>. So sphere B lands on the floor some point between the table's edge and the point X (A).
Answer:
Gravity pulls objects toward Earth.
The rate of acceleration due to gravity is 9.8 m/s2.
Weight on Earth’s surface is a result of gravity’s pull.
Explanation:
these are the answers for e2020
Answer:
Acceleration = 311.2 Km/hr²
Explanation:
Given: Radius of the Orbit r= 3.56 × 10⁶ km
Period of the orbit = 28 days = 672 hrs
Sol: We have Fc = MV²/r
⇒M ac = MV²/r
⇒ac = V²/r
First we have to Speed V so for this we have to find the circumference ( distance covered by the moon in one orbit)
⇒ Circumference= 2 π r
= 2 × 3.13149 × 3.56 × 10⁶ km
= 22,368,139.69 Km
Now Speed = Distance /time
Speed = 22,368,139.69 Km / 672 hrs
Speed V = 33,285.92 Km/Hr
Now
ac = V²/r = (33,285.92 Km/hrs)² / 3.56 × 10⁶ km
ac = 311.2 Km/hr²
The best and most correct answer among the choices provided by the question is decreases <span>.
</span>The potential energy of the object <span>decreases.</span>
Hope my answer would be a great help for you.
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Answer:
I think that the answer is convection.
Explanation:
Hope this helps.