All categories

3 years ago

When the units are smaller, we need (more / less) of them.

Physics

2 answers:

lbvjy [14]3 years ago

6 0

Answer:

more..................

Arada [10]3 years ago

4 0

Answer:

If you are referring units to the metric system, I think the answer would be less.

(I'm not completely sure)

Explanation:

I say this because for example, if you have a prescription for 5,000 mg of medicine, and upon getting it filled, the dosage than decimeters (dm), so you expect there to be more than one dm in a km. (Since you are going from a larger unit to a smaller unit, you multiply). Meters is larger than centimeters, so you expect your answer to be less than 7,225.

Hope this helps and makes sense! :D

You might be interested in

A simple model of a hydrogen atom is a positive point charge +e (representing the proton) at the center of a ring of radius a wi

Norma-Jean [14]

Answer:

Now e is due to the ring at a

We say

1/4πEo(ea/ a²+a²)^3/2

= 1/4πEo ea/2√2a³

So here E is faced towards the ring

Next is E due to a point at the centre

E² = 1/4πEo ( e/a²)

Finally we get the total

Et= E²-E

= e/4πEo(2√2-1/2√2)

So the direction here is away from the ring

8 0

3 years ago

Can you access an instance variable from a static method? explain why or why not.

marusya05 [52]

The reason a static method can't access instance variable is because static references the class not a specific instance of the class so there is no instance variable to access.

5 0

4 years ago

You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of

Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

$\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}$

$\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}$

Solve s'

$\frac{1}{s'} = \frac{2}{1.50 m} - \frac{1}{2.0 m}$

$\frac{1}{s'} = 1.833 m$

$s' = - 0.545 m$

To determine the speed of the trick to the highway

$\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}$

$\frac{ds}{dt} = 26.88 m/s$

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0

3 years ago

A horizontal force of 25 N is required to push a wagon across a sidewalk at a constant speed.

lions [1.4K]

Answer:

a. The net force acting on the wagon is zero

b. The value of the force of friction is 25 N

c. The effect would be is the frictional force must be increase

Explanation:

Lets explain how to solve the problem

A horizontal force of 25 N is required to push a wagon across a sidewalk

at a constant speed

→ Constant speed means acceleration is zero

→ Force = mass × acceleration

→ Force = mass × 0

→ Force = 0

The net force acting on the wagon is zero

The wagon moves with constant speed, then

→ ∑ force = 0

There are two forces acting on the wagon external force of 25 N,

and the frictional force which is opposite to the direction of motion

→ 25 - Frictional force = 0

→ Frictional force = 25 N

The value of the force of friction is 25 N

The force increased to 30 N

If the wagon still moves with constant speed

Due to Newton's law ∑ force in the direction of motion = mass ×

acceleration, but acceleration is 0 because the wagon moves with

constant speed, then ∑ F = 0

So the frictional force must increase to 30 N

The effect would be is the frictional force must be increase

If the frictional force does not increase the wagon will accelerate

6 0

3 years ago

Se transmiten ondas transversales en una cuerda tensada orientada sobre el eje x. La función de ondas correspondientes es y= 5.0

TEA [102]

Answer:

Explanation:

Whats the entire question?

4 0

3 years ago