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labwork [276]
3 years ago
5

What is the strongest type of van der Waals force that exists between molecules of ammonia, NH3?

Chemistry
2 answers:
Marianna [84]3 years ago
6 0
It is hydrogen bond(as well as fh, and h2o), intermolecular force.
sergiy2304 [10]3 years ago
4 0

Answer:  Intermolecular Hydrogen Bonding

Explanation:  Ammonia molecule is  planar molecule in which 3 hydrogen atoms are attached to the nitrogen atom leaving a pair of lone pair of electrons on the latter.

As we know that the hydrogen bonding is the result of the electrostatic forces of attraction between the hydrogen atom attached with the electronegative atom of one compound with the electronegative atom of the other.

Thus the strongest type of van der waal forces of attraction which can occur in molecules of ammonia is Intermolecular Hydrogen Bonding

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Consider the following genotype Yy Ss Hh
Ilya [14]

From: Yy Ss Hh 8 different gametes can be formed

  • 5 Eye Color Genes = 243 genotypes
  • 10 Eye Color Genes= 59049 genotypes
  • 20 Eye Color Genes= 3,486,784,401 genotypes

This is further explained below.

<h3>What is a gamete?</h3>

Generally, Gametes are the cells of an organism that are responsible for reproduction. In certain contexts, they are also referred to as egg cells and sperm cells.

The popular word for female gametes is ova, whereas the common name for male gametes is sperm. Ovum and egg cells are other frequent names for female gametes.

Gametes are instances of haploid cells since they only contain a single copy of each chromosome. Haploid cells are described as having only one copy of each chromosome.

In conclusion, For 5 Eye Color Genes

3^n is implored hence

3^5=243 genotypes

Repeating said pattern e have

  • 10 Eye Color Genes= 59049 genotypes
  • 20 Eye Color Genes= 3,486,784,401 genotypes

Read more about gamete

brainly.com/question/2569962

#SPJ1

CQ

4. Consider the following genotype: Yy Ss Hh. We have now added the gene for height: Tall (H) or Short (h).

a. How many different gamete combinations can be produced?

b. Many traits (phenotypes), like eye color, are controlled by multiple genes. If eye color were controlled by the number of genes indicated below, how many possible genotype combinations would there be in the following scenarios?

a. 5 Eye Color Genes:

b. 10 Eye Color Genes:

c. 20 Eye Color Genes:

6 0
1 year ago
What kind of chemical bonds are represented by the product in the following diagram?
katovenus [111]
The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.
4 0
3 years ago
Calculate the amount of mole of iron produced from the reaction of 15.9 grams of iron oxide.
Usimov [2.4K]

Answer:

0.19875

Explanation:

nFe2O3=0.099375

nFe=2nFe2O3=0.19875

3 0
3 years ago
Which of the following would be a clue that a rock is igneous?
ryzh [129]

Answer:

A

Explanation:

they usually have that Crystal like thing in them... since they are formed from Lava

7 0
3 years ago
Read 2 more answers
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
3 years ago
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