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SIZIF [17.4K]
3 years ago
10

A hoop is rolling without slipping along a horizontal surface with a forward speed of 5.50 m/s when it starts up a ramp that mak

es an angle of 25.0° with the horizontal. What is the speed of the hoop after it has rolled 3.00 m up as measured along the surface of the ramp
Physics
1 answer:
Burka [1]3 years ago
5 0

Answer:

v_f = 4.22 m/s

Explanation:

As we know by energy conservation

initial total energy = final total energy

so we have

\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = \frac{1}{2}mv_f^2 + \frac{1}{2}I\omega_f^2 + mgL sin\theta

so we have

v = R \omega

I = mR^2

mv_i^2 = mv_f^2 + mgL sin\theta

5.50^2 = v_f^2 + (9.81)(3) sin25

30.25 - 12.43 = v_f^2

v_f = 4.22 m/s

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