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3 years ago

¿Cuántos moles de bióxido de Nitrógeno (NO 2) se forman cuando reaccionan 5 moles de Nitrógeno (N 2)?

Chemistry

1 answer:

o-na [289]3 years ago

5 0

Answer:

10 moles de NO2

Explanation:

Tenemos la ecuación de la reacción como sigue;

N2 (g) + 2 O2 (g) → 2 NO2 (g)

Asi que;

Si 1 mol de nitrógeno produce 2 moles de NO2

5 moles de nitrógeno producirán 5 * 2/1 = 10

Por tanto, se producen 10 moles de NO2 moles

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A lead ball has a mass of 55.0 grams and a density of 11.4 g/cm3. What is the volume of the ball?

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Read 2 more answers

A weather balloon is inflated to a volume of 27.3 L at a pressure of 738 mmHg and a temperature of 26.9 ∘C. The balloon rises in

sertanlavr [38]

Answer:

The new volume of the balloon is 46.1 L

Explanation:

Step 1: Data given

Initial volume of the balloon = 27.3 L

Initial pressure in the balloon = 738 mmHg = 0.97105 atm

Initial temperature in the balloon = 26.9 °C = 300.05 K

The pressure decreases to 375 mmHg = 0.493421 atm

The temperature lowers to -15.6 °C = 257.55 K

Step 2: Calculate the volume

P1*V1 / T1 = P2 *V2 / T2

⇒with P1 = the Initial pressure = 738 mmHg = 0.97105 atm

⇒with V1 = Initial volume of the balloon = 27.3 L

⇒with T1 = Initial temperature in the balloon = 26.9 °C = 300.05 K

⇒with P2 = the decreased pressure = 0.493421 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the lowered temperature = 257.55 K

0.97105 * 27.3 / 300.05 = 0.493421*V2 / 257.55

V2 = 46.1 L

The new volume of the balloon is 46.1 L

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