1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NemiM [27]
3 years ago
7

Which applications, either for diagnostic purposes or for therapeutic purposes, do not involve ionizing radiation? Check all tha

t apply.
Physics
2 answers:
Ymorist [56]3 years ago
6 0

Answer: I do not know (is this an RP question? ;-;)

Explanation:

Marina86 [1]3 years ago
4 0

Answer:

Applications in which ionizing radiation are not used are  

MRI

ultrasound

laser surgery

Explanation:

hope its right

bestfriend

You might be interested in
Explain the range of effectiveness of each fundamental force by describing the distance that each force influence nearby matter
Bas_tet [7]

Answer:

Actually, gravity is the weakest of the four fundamental forces. Ordered from strongest to weakest, the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity.

6 0
3 years ago
A space vehicle is traveling at 5320 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The
labwork [276]

Answer:

5398.4km/h

Explanation:

IN THIS CASE THE MOMENTUM IS CONSERVED. THE VALUE OF MOMENTUM OF ONE COMBINED ROCKET WILL BE SAME AS OF TWO COMBINED.

Let mass of module be m

then

mass of motor  = 4m  (four times the mass of rocket module)

total mass = m + 4m = 5m

combined velocity = V = 5320kph

Let

absolute (relative to earth)motor velocity after disengagement = v

then

rocket module velocity (relative to earth) after disengagement = v+98  (relative velocity = 98)

momentum conservation equation

combined momentum = module momentum + motor momentum

(m+4m)V = m(v+98) + 4m*v

5mV = 98m+mv + 4mv

5V = 98+v + 4v (m cancels out)

5V - 98 = 5v

((5*5320)-98)/5 = v

v = 5300.4 km/h

velocity of rocket module relative to earth = v +98

                                                                       = 5300.4 + 98

                                                                       = 5398.4km/h  

4 0
4 years ago
Which types of electromagnetic radiation can our senses detect?
GuDViN [60]
<span>Our eyes can detect visible radiation, our skin can detect infra-red, our skin can also react to ultra-violet radiation by tanning, and producing skin cancers. 



</span>Our brains can react directly to the impact of gamma rays ( as "seen" by astronauts ) 
<span>and some microwaves will cause us to heat up internally. 
</span>

<span>While radio waves and ELF waves seem to ignore us totally without the aid of aerials and amplifiers. </span>

3 0
3 years ago
Why does a plane move even when the wind is pushing against it?
boyakko [2]
A plane has more mass in it. Also, the engine is very strong which it makes the plane able to push through the wind. When the wind is pushing, it goes by it because of the engine.
3 0
3 years ago
Read 2 more answers
At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m2 . A fan is 30 m from the loudspea
marshall27 [118]

The concepts used to solve this problem are sound power, area of ear drum, and inverse square law.  First find the intensity I_2 using inverse square law for different distances. Then find the area of the ear drum using the diameter and finally find the energy transferred to each ear drum in one second. Intensity is inversely proportional to the square of the distance from the source:

I \propto \frac{1}{r^2}

Here,

r = Distance from the source,

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

I_2 = I_1 \frac{r_1^2}{r_2^2}

I_2 = (0.10W/m^2)(\frac{(1m)^2}{(30m)^2})

I_2 = 1.11*10^{-4}W/m^2

Now the expression for the Area of ear drum is

A= \frac{\pi d^2}{4}

A = \frac{\pi (8.4mm\frac{1m}{10^3mm})^2}{4}

A = 5.5*10^{-5}m^2

The expression for Sound power is

P = AI_2

Replacing,

P= (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)

P = 6.1*10^{-9}W = 6.1*10^{-9}J/s

Therefore the energy reached per second is 6.1*10^{-9}J

4 0
3 years ago
Other questions:
  • What force is necessary to accelerate a 1250 kg car at a rate of 40 m/s^2?
    13·2 answers
  • In which activity is no work done?
    15·2 answers
  • A long-distance runner is running at a constant speed of 6 m/s.
    15·1 answer
  • Half-life is the time a. For half of a material to decay into energy b. For half of a material to decay into free protons, neutr
    13·1 answer
  • The range of wavelengths for visible light is from 3.9*10^-7m. What is the corresponding range of frequencies for visible light
    15·1 answer
  • a) A magnet falls through a loop of wire with the southpole entering first. As the south pole approaches the loop, what isthe di
    9·1 answer
  • what was the important new result shown by joules experiment involving paddles stirring known quantities of water?
    13·1 answer
  • Compare the outermost electrons of an atom with the inner most electrons of an atom in terms of energy
    5·1 answer
  • The width, length, and height of a large, custom-made shipping crate are 1.12 m, 1.25 m, and 0.83 m, respectively. The volume of
    15·1 answer
  • Why are Substances used as perfumes are usually in a liquid state
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!