Answer:
Radial acceleration of moon is ![a_{r} = 2.246\times 10^{-3}](https://tex.z-dn.net/?f=a_%7Br%7D%20%3D%202.246%5Ctimes%2010%5E%7B-3%7D)
Explanation:
Given :
Time period
sec
Distance from center of moon to planet
m
From the equation of radial acceleration,
![a_{r} = r\omega ^{2}](https://tex.z-dn.net/?f=a_%7Br%7D%20%3D%20r%5Comega%20%5E%7B2%7D)
Where ![\omega = 2\pi f = \frac{2\pi }{T}](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20f%20%3D%20%5Cfrac%7B2%5Cpi%20%7D%7BT%7D)
So
Now moon's radial acceleration,
![a_{r} = 225 \times 10^{6} \times (3.16 \times 10^{-6} )^{2}](https://tex.z-dn.net/?f=a_%7Br%7D%20%3D%20225%20%5Ctimes%2010%5E%7B6%7D%20%5Ctimes%20%283.16%20%5Ctimes%2010%5E%7B-6%7D%20%29%5E%7B2%7D)
![a_{r} = 2246.76 \times 10^{-6}](https://tex.z-dn.net/?f=a_%7Br%7D%20%3D%202246.76%20%5Ctimes%2010%5E%7B-6%7D)
![\frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:
F = (k*Q1*Q2)/d^2
k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.
As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.
Crude oil has parts of decomposed dinosaurs and plants from millions of years ago. When the sun gave energy to the plants for their growth, the dinasours ate them which is now is stored in the oil today. So the sun gave energy to plants, dinosaurs ate them, pasted away and decomposed, then we drill and use it as oil.
That's true.
And I'll go ya a better one:
If the object is moving or not moving, at a constant or changing speed, in a straight or curvy line, and the forces on it do not cancel out and add up to zero, the object will accelerate.