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olasank [31]
3 years ago
10

Which of the following is an inclined plane wrapped around a rod?

Physics
2 answers:
zlopas [31]3 years ago
8 0

Alright well the Answer to your question is A). Screw

Hope this helps have a nice day : )

If u want i can explain why

Akimi4 [234]3 years ago
6 0

Answer:

answer is screw my good fellow

Explanation:

You might be interested in
An electron that has an instantaneous velocity of ???? = 2.0 × 106 m ???? ???? + 3.0 × 106 m ???? ???? is moving through the uni
Setler79 [48]

Explanation:

It is given that,

Velocity of the electron, v=(2\times 10^6i+3\times 10^6j)\ m/s

Magnetic field, B=(0.030i-0.15j)\ T

Charge of electron, q_e=-1.6\times 10^{-19}\ C

(a) Let F_e is the force on the electron due to the magnetic field. The magnetic force acting on it is given by :

F_e=q_e(v\times B)

F_e=1.6\times 10^{-19}\times [(2\times 10^6i+3\times 10^6j)\times (0.030i-0.15j)]

F_e=-1.6\times 10^{-19}\times (-390000)(k)

F_e=6.24\times 10^{-14}k\ N

(b) The charge of electron, q_p=1.6\times 10^{-19}\ C

The force acting on the proton is same as force on electron but in opposite direction i.e (-k). Hence, this is the required solution.

8 0
3 years ago
A bus travelling 30.0 km/h east has a constant increase in speed of 1.5 m/s. What is its velocity 6.8s later
alekssr [168]

Answer:

8.72 seconds before

Explanation:

and 27.1 secs after

7 0
3 years ago
At its maximum speed, a typical snail moves about 4.0 m in 5.0 min.
stiv31 [10]

Answer:

Explanation:

Given

Distance = 4.0m

Time = 5.0 mins = 300secs

Required

Average speed

Average speed = Distance/Time

Average speed = 4.0/300

Average speed = 0.01333m/secs

Hence the average speed of the snail is 0.01333m/s

6 0
2 years ago
Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They
timama [110]

Answer:

c. 48 cm/s/s

Explanation:

Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They determine that a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with a mass of 2M when acted upon by a net force of 2F?

from newtons second law of motion ,

which states that change in momentum is directly proportional to the force applied.

we can say that

f=m(v-u)/t

a=acceleration

t=time

v=final velocity

u=initial velocity

since a=(v-u)/t

f=m*a

force applied is F

m =mass of the object involved

a is the acceleration of the object involved

f=m*48.........................1

in the second case ;a mass of 2M when acted upon by a net force of 2F

f=ma

a=2F/2M

substituting equation 1

a=2(M*48)/2M

a=. 48 cm/s/s

6 0
3 years ago
An insulated rigid tank contains 3 kg of H2O in the form of a saturated mixture of liquid and vapor at a pressure of 150 kPa and
Andre45 [30]

Answer:

change in entropy is 1.44 kJ/ K

Explanation:

from steam tables

At 150 kPa

specific volume

Vf = 0.001053 m^3/kg

vg = 1.1594 m^3/kg

specific entropy values are

Sf = 1.4337 kJ/kg K

Sfg = 5.789 kJ/kg

initial specific volume is calculated as

v_1 = vf + x(vg - vf)

      = 0.001053 + 0.25(1.1594 - 0.001053)

v_1 = 0.20964  m^3/kg

s_1 = Sf + x(Sfg)

     = 1.4337 + 0.25 \times 5.7894 = 2.88 kJ/kg K

FROM STEAM Table

at 200 kPa

specific volume

Vf = 0.001061 m^3/kg

vg = 0.88578 m^3/kg

specific entropy values are

Sf = 1.5302 kJ/kg K

Sfg = 5.5698 kJ/kg

constant volume  sov_1 -  v_2  = 0.29064 m^3/kg

v_2 = v_1 = vf + x(vg - vf)

       =0.29064 = x_2(0.88578 - 0.001061)

x_2 = 0.327

s_2 = 1.5302 + 0.32 \times 5.5968 = 3.36035 kJ/kg K

Change in entropy \Delta s = m(s_2 - s_1)

              =3( 3.36035 - 2.88) =  1.44 kJ/kg

8 0
3 years ago
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