A day on a distant planet observed orbiting a nearby star is 21.5 hr. Also, a year on the planet lasts 69.3 Earth days. In other
1 answer:
Answer:
Part A
The angular speed of rotation of the plane is 8.11781 × 10⁻⁵ rad/s
Part B
The angular speed of orbit of the planet is 1.04938 × 10⁻⁶ rad/s
Explanation:
The parameters of the planet are;
The duration of a day on the distant planet = 21.5 hr.
The duration of a year on the distant planet = 69.3 Earth days
Part A
The duration of a day = The time to make one complete revolution of 2·π radians
∴ The average angular speed about its axis, = Angle turned/Time
∴ = 2·π/(21.5 × 60 × 60) s ≈ 8.11781 × 10⁻⁵ rad/s
The average angular speed of the planet about its own axis, = 8.11781 × 10⁻⁵ rad/s
The angular speed of rotation of the plane = 8.11781 × 10⁻⁵ rad/s
Part B
The time it takes the planet to revolve round the neighboring star once = 69.3 Earth days
Therefore, the average angular speed of the planet around its neighboring star, , is given as follows;
= 2·π/((69.3 × 24 × 60 × 60) s) = 1.04938 × 10⁻⁶ rad/s
The average angular speed of orbit, = 1.04938 × 10⁻⁶ rad/s
The angular speed of orbit of the planet, = 1.04938 × 10⁻⁶ rad/s.
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Wavelength of the thin beam of light, λ = 50 μm
Distance of the screen from the slit, D = 3.00 m
Width of the fringe, Δy = ±8.24 mm
Therefore, width of the slit is given by :
= 0.000018203 m
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= 0.018 mm
The intensity of light is given by :
, where
Now,
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