Hi there!
Recall the equation for spring potential energy:
k = Spring constant (N/m)
x = extension of spring from equilibrium (m)
PE = Potential Energy (J)
Plug in the given values:
A day on a distant planet observed orbiting a nearby star is 21.5 hr. Also, a year on the planet lasts 69.3 Earth days. In other
1 answer:
Answer:
Part A
The angular speed of rotation of the plane is 8.11781 × 10⁻⁵ rad/s
Part B
The angular speed of orbit of the planet is 1.04938 × 10⁻⁶ rad/s
Explanation:
The parameters of the planet are;
The duration of a day on the distant planet = 21.5 hr.
The duration of a year on the distant planet = 69.3 Earth days
Part A
The duration of a day = The time to make one complete revolution of 2·π radians
∴ The average angular speed about its axis, = Angle turned/Time
∴ = 2·π/(21.5 × 60 × 60) s ≈ 8.11781 × 10⁻⁵ rad/s
The average angular speed of the planet about its own axis, = 8.11781 × 10⁻⁵ rad/s
The angular speed of rotation of the plane = 8.11781 × 10⁻⁵ rad/s
Part B
The time it takes the planet to revolve round the neighboring star once = 69.3 Earth days
Therefore, the average angular speed of the planet around its neighboring star, , is given as follows;
= 2·π/((69.3 × 24 × 60 × 60) s) = 1.04938 × 10⁻⁶ rad/s
The average angular speed of orbit, = 1.04938 × 10⁻⁶ rad/s
The angular speed of orbit of the planet, = 1.04938 × 10⁻⁶ rad/s.
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Answer:
La distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.
Explanation:
Asumamos que ambos cuerpos son partículas, la fuerza de atracción (), en newtons, entre ambos cuerpos se define mediante la Ley de Newton de la Gravitación Universal, cuya ecuación es:
(1)
Donde:
- Constante de la gravitación universal, en metros cúbicos por kilogramo-segundo cuadrado.
- Masas de los cuerpos, en kilogramos.
- Distancia entre los cuerpos, en metros.
Si sabemos que ,
,
y
, entonces la distancia entre los dos cuerpos es:
Es decir, la distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.