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Svet_ta [14]
3 years ago
11

An engineer thinks that changing the catalyst used in a chemical reaction will

Chemistry
1 answer:
hoa [83]3 years ago
5 0

Answer:

B. Identify solutions to the problem.

Explanation:

In the case described above, the engineer has already designed and attempted to manufacture a prototype for the process. The design of the process must have also been carefully researched and planed.

However, he identified the problem of low yield and is now working towards identifying solutions to the problem. One option he seeks to explore according to the question is to change the catalyst used in the reaction.

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HELPPPPPPPPPPPPPPPPPPPPPP
ololo11 [35]

Answer:

c

Explanation:

7 0
3 years ago
An aqueous basic solution has a concentration of 0. 050 m and kb is 4. 4 × 10^-4. What is the concentration of hydronium ion in
Alex_Xolod [135]

An aqueous basic solution has a concentration of 0. 050 m and kb is 4. 4 × 10^-4, the concentration of hydronium ion in this solution (m) is 2.234 × 10⁻¹² M.

Methylamine is an amine which is an organic weak base. Its chemical formula is CH₃NH₂. When it undergoes hydrolysis wherein water is acting as an acid, the reaction would be

CH₃NH₂ + H₂O ⇆  CH₃NH₃ + OH⁻

Then, we use the ICE analysis which stands for Initial-Change-Equilibrium.

CH₃NH₂ + H₂O ⇆  CH₃NH₃ + OH⁻

Initial                    0.05          -                 0         0

Change                 -x                              +x       +x

----------------------------------------------------------------------------

Equilibrium         0.05-x                           x          x

Then, we use the equation for the equilibrium constant of basicity.

Kb = [CH₃NH₃][OH⁻]/[CH₃NH₂] = 4.4×10⁻⁴

4.4×10⁻⁴ = [x][x]/[0.05-x]

[x] = 4.4756×10⁻³

Here, variable x denotes the number of moles of the substance which is involved in the reaction. Since the equilibrium amount of OH⁻ is equal to x, then the concentration of OH⁻ is also 4.4756×10⁻³. Thus,

pOH = -log[OH⁻]

pOH = -log[4.4756×10⁻³] = 2.35

The relationship between pOH and pH is that pH + pOH = 14. Thus,

pH = 14 - 2.35 = 11.65

pH = -log[H⁺]

11.65 = -log[H⁺]

[H⁺] = 2.234 × 10⁻¹² M

Thus, we find the concentration of solution is 2.234 × 10⁻¹² M.

Learn more about aqueous solution: brainly.com/question/11097800

#SPJ4

5 0
2 years ago
According to the Energy Information Administration (EIA), oil accounts for what percentage of the U.S. energy mix?
stich3 [128]

Answer: answer is b 29%

Explanation:

7 0
3 years ago
The seafloor and continental land are similar in age true or false
EastWind [94]

false my dude......;;;;;;;;;;;;;;;[[[[[[

7 0
3 years ago
Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1
anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

m_{O_2}=8.65g-8.00g=0.65g

Learn more:

  • brainly.com/question/14502981
  • brainly.com/question/14236219
3 0
2 years ago
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