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Zigmanuir [339]
3 years ago
9

The substance krypton has the following properties normal melting point 115.9 K normal boiling point: 119.8 K triple point: 0.72

atm. 115.8 K critical point: 54.3 atm. 209.4 K A sample of krypton at a pressure of 1.00 atm and a temperature of 149.2 K is cooled at constant pressure to a temperature of 107.8 K Which of the following are true?
a) The final state of the substance is a solid
b) One or more phase changes will occur
c) The final state of the substance is a liquid
d) The sample is initially a gas
e) The solid initially present will vaporize.
Chemistry
1 answer:
Rasek [7]3 years ago
3 0

Answer:

B. One or more phase change occur

C. the final state of substance is liquid

D. the sample initially gas

Explanation:

The pressure p = 1.00 atm

The temperature t = 149.2K

The temperature > 119.8K

119.8K being the normal boiling point.

This shows that the krypton is a gas

After it has cooled the pressure = 1.00 atm

The temperature T dropped to 107.8K

T < 115.9K

The melting point has been put as 115.9K

This is a liquid. The final state of the substance is a liquid. Since the temperature is less than the melting point and the pressure is 1.00 atm

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When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2 Al ( s ) + 6 HCl ( aq ) ⟶ 2AlCl3 ( aq ) +
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Answer:

The answer to your question is  V = 19.9 L

Explanation:

Data

mass of Al = 8.60 g

volume of H₂ = ?

Balanced chemical reaction

                 2Al  +  6HCl  ⇒   2AlCl₃  +  3H₂

1.- Use proportions to calculate the mass of H₂ produced

Atomic mass of Al = 2 x 27 = 54 g

Atomic mass of H₂ = 6 x 1 = 6 g

                54 g of Al -------------------- 6 g of H₂

                  8 g  of Al -------------------  x

                  x = (8 x 6) / 54

                  x = 48 / 54

                  x = 0.89 g of H₂

2.- Calculate the volume of H₂

- Convert the H₂ to moles

                    1 g of H₂ --------------- 1 mol

                   0.89 g    ---------------- x

                    x = 0.89 moles

                    1 mol of H₂ -------------- 22.4 l

                   0.89 moles  ------------- x

                    x = (0.89 x 22.4) / 1

                   x = 19.9 L                        

6 0
3 years ago
How many calories are absorbed in a process that absorbs 0.128 joules?
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Answer:

There are 0.0305 calories in 0.128 joules

Explanation:

Given that,

Heat absorbed, Q = 0.128 J

We need to find the heat energy absorbed in calories.

We know that the relation between joules and calories is as follows :

1 calorie = 4.184 J

1 J = (1/4.184) J

So,

0.128\ J=\dfrac{0.128 }{4.184}\\\\=0.0305\ cal

So, there are 0.0305 calories in 0.128 joules

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Answer:

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An acid, like HCI, would...
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Explanation:

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