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emmainna [20.7K]
3 years ago
15

. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Wit

hout doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it
Chemistry
1 answer:
never [62]3 years ago
8 0

Answer:

Answer is explained in the explanation section below.

Explanation:

This question is requires the diagram, which I have drawn and it is attached in the attachment below. Please for this answer, refer to the diagram attached in the attachment below.

Referring to the diagram, attached. As we know that, Allylic secondary carbocations are more stable than Allylic tertiary carbocations.

Hence,

C2 will have a more positive charge since a tertiary carbocation (C2) is more stable than a secondary carbocation (C4). Therefore, the resonance structure will favor the positive charge at C2.

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The reaction between calcium carbonate (CaCO3) and HCl produces calcium chloride (CaCl2), carbon dioxide (CO2), and water (H2O).
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When the hydrogen chloride concentration doubles, the number of collisions between the reactants becomes increased, which causes the rate of the forward reaction to be faster.

<h3>What is the rate of a reaction?</h3>

The rate of a reaction is how fast a chemical reaction occurs i.e. the conversion of reactants to products.

The rate of a chemical reaction can be influenced by certain factors including the concentration of reactants.

The more the concentration of a reactant, the more the collision between the reactants and hence, the faster the reaction will proceed.

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7 0
2 years ago
How many moles are in 3.27 x 1027 atoms of carbon (C)? ​
rusak2 [61]

Answer:

Try:

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1 mole

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3. How many moles are in 2.5g of lithium?

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4. Find the mass of 4.8moles of iron.

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Explanation:

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5 0
3 years ago
A reaction mechanism is defined as the sequence of reaction steps that define the pathway from reactants to products. Each step
olga55 [171]

Answer: (a) K *[A][B]^2

(b) The answer is B

Explanation:

A)

Step1:A+B<--> C (fast)

Step2: B+C→D(slow)

Rate depends on slowest step.

so,

rate = k' [B][C] ...eqn 1

But C is intermediate.so use step 1

Since 1st step is an equilibrium,

Kc = [C] /[A][B]

so,

[C] = Kc [A][B] ...eqn 2

put eqn 2 in eqn 1

rate = k' *[B] * Kc [A][B]

= k'Kc*[A][B]^2

= K *[A][B]^2 {writing k'Kc = K}

Answer: K *[A][B]^2

B)

Answer is B

Since rate depends on slowest step.

if slowest step is:

X2Y2+Z2→X2Y2Z+Z

then only,

rate= k[X2Y2][Z2]

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