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rjkz [21]
3 years ago
8

Select the correct answer from each drop-down menu.

Engineering
1 answer:
alekssr [168]3 years ago
5 0

Answer:

James would have to determine the LOAD BEARING CAPACITY OF THE SOIL  and the DESINGH OF THE BUILDING to decide at what depth he should lay the foundation.

Explanation:

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A __________ is a single lane used by drivers to enter and exit a freeway. a) Climbing lane b) Weave lane c) Thru lane d) Offset
Rufina [12.5K]

A Weave lane is a single lane used by drivers to enter and exit a freeway.

<h3>What is this lane about?</h3>

Weave lanes are known to be lanes that acts as an entrance and exits for a lot of cars in highways.

Hence, one can say that A Weave lane is a single lane used by drivers to enter and exit a freeway.

Learn more about Weave lane from

brainly.com/question/10828527

#SPJ1

6 0
2 years ago
What two elements make up fuel oil​
nordsb [41]
Carbon and hydrogen!!
4 0
3 years ago
. . . . . . . . . . ..........
Naddika [18.5K]

Answer: Thx for points...

Explanation:

Heres Random Info About Enginnering (because why not): Engineers are involved in all aspects of interactive TV technology, from designing new cables, to creating new film emulsions, to engineering better sound quality. This technology allows viewers to select any program, film, or game from more than 500 channels. Engineers play an instrumental role in the theme park industry?

Hope This Helps Someday!

5 0
3 years ago
Steam enters an adiabatic turbine at 10MPa and 500 C and leaves at 10 kPa with a quality of 90%. Neglecting the changes in kinet
Amanda [17]

Answer:

flow ( m ) = 4.852 kg/s

Explanation:

Given:

- Inlet of Turbine

        P_1 = 10 MPa

        T_1 = 500 C

- Outlet of Turbine

        P_2 = 10 KPa

        x = 0.9

- Power output of Turbine W_out = 5 MW

Find:

Determine the mass ow rate required

Solution:

- Use steam Table A.4 to determine specific enthalpy for inlet conditions:

          P_1 = 10 MPa

          T_1 = 500 C            ---------- > h_1 = 3375.1 KJ/kg

- Use steam Table A.6 to determine specific enthalpy for outlet conditions:

          P_2 = 10 KPa       -------------> h_f = 191.81 KJ/kg

          x = 0.9                  -------------> h_fg = 2392.1 KJ/kg

          h_2 = h_f + x*h_fg

          h_2 = 191.81 + 0.9*2392.1 = 2344.7 KJ/kg

- The work produced by the turbine W_out is given by first Law of thermodynamics:

          W_out = flow(m) * ( h_1 - h_2 )

          flow ( m ) = W_out / ( h_1 - h_2 )

- Plug in values:

          flow ( m ) = 5*10^3 / ( 3375.1 - 2344.7 )

          flow ( m ) = 4.852 kg/s

3 0
3 years ago
Implement this C program by defining a structure for each payment. The structure should have at least three members for the inte
Klio2033 [76]

Answer:

#include<stdio.h>

#include<math.h>

void output_amortized(float loan_amount,float intrest_rate,int term_years)

{

  int i,j;                       //Month

  int payments;                   //Number of payments  

  float loanAmount;               //Loan amount

  float anIntRate;               //Yealy interest Rate

  float monIntRate;               //Monthly interest rate

  float monthPayment;           //Monthly payment

  float balance;                   //Balance due

  float monthPrinciple;           //Monthly principle paid

  float monthPaidInt;           //Month interest paid

 

  balance=loan_amount;

  //Calculations

  //Monthly interest rate

  monIntRate = ((intrest_rate/(100*12)));

  //Monthly payment

  payments=term_years;  

  monthPayment = (loan_amount * monIntRate * (pow(1+monIntRate, payments)/(pow (1+monIntRate, payments)-1)));

  monthPaidInt = balance * monIntRate;

  //Amount paid to principle

  monthPrinciple = monthPayment-monthPaidInt;

  //New balance due

  balance = balance - monthPrinciple;

 

  printf("\n\nMonthly payment should be :%.2f\n\n",monthPayment);

  printf("============================AMORTIZATION SCHEDUAL==========================\n");

  printf("#\tPayment\t\tIntrest\t\tPrinciple\t\tBalance\n");

 

  for(i=0;i<payments;i++)

  {

      printf("%d%9c%.2f%9c%.2f%16c%.2f%14c%.2f\n",(i+1),'$',monthPayment,'$',monthPaidInt,'$',monthPrinciple,'$',balance);

      monthPaidInt = balance * monIntRate;

      //Amount paid to principle

      monthPrinciple = monthPayment-monthPaidInt;

      //New balance due

      balance = balance - monthPrinciple;

  }

}

int main()

{

  float principle,rate;

  int termYear;

  printf("Enter the loan amount: $");

  scanf("%f",&principle);

  printf("Enter the intrest rate :%");

  scanf("%f",&rate);

  printf("Enter the loan duration in years: ");

  scanf("%d",&termYear);

  output_amortized(principle,rate,termYear);

}

Explanation:

see output

6 0
3 years ago
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