The formula SF_2 expresses one-third the amount of F.
The F:S ratio in the first compound is 6:1.
We want a compound with one third the amount of F, so F:S = 2:1.
The simplest formula with this ratio is SF_2.
Answer:
0.387 g
Explanation:
pH of the buffer = 1
V = Volume of solution = 100 mL
[HA] = Molarity of HA = 0.1 M
= Acid dissociation constant = 
(assuming base as 
)
Molar mass of base = 322.2 g/mol
pKa is given by
From the Henderson-Hasselbalch equation we get
![pH=pK_a+\log\dfrac{[A^-]}{[HA]}\\\Rightarrow pH-pK_a=\log\dfrac{[A^-]}{[HA]}\\\Rightarrow 10^{pH-pK_a}=\dfrac{[A^-]}{[HA]}\\\Rightarrow [A^-]=10^{pH-pK_a}[HA]\\\Rightarrow [A^-]=10^{1-1.92}\times0.1\\\Rightarrow [A^-]=0.01202\ \text{M}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%5Cdfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%5C%5C%5CRightarrow%20pH-pK_a%3D%5Clog%5Cdfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%5C%5C%5CRightarrow%2010%5E%7BpH-pK_a%7D%3D%5Cdfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%5C%5C%5CRightarrow%20%5BA%5E-%5D%3D10%5E%7BpH-pK_a%7D%5BHA%5D%5C%5C%5CRightarrow%20%5BA%5E-%5D%3D10%5E%7B1-1.92%7D%5Ctimes0.1%5C%5C%5CRightarrow%20%5BA%5E-%5D%3D0.01202%5C%20%5Ctext%7BM%7D)
Moles of base
Mass of base is given by
The required mass of the base is 0.387 g.
If the bonds are held together tightly, as an ionic bond or even a covalent bond, there will need to be a strong force to separate those bonds. This would by why their would be a high melting point. Another reason would be re-activity. <span />
Answer:
by pumping blood throughout the body.
Explanation:
