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Amanda [17]
3 years ago
8

A solenoid that is 133 cm long has a radius of 2.99 cm and a winding of 1740 turns; it carries a current of 3.91 A. Calculate th

e magnitude of the magnetic field inside the solenoid.
Physics
1 answer:
erica [24]3 years ago
5 0

Answer:

The value is  B = 0.0643 \ T  

Explanation:

From the question we are told that

   The length of the solenoid is  L =  133 \  cm  = 1.33 \  m

     The radius is  r = 2.99 \  cm   = 0.0299 \  m

     The number of turns is N  = 1740 \ turns

     The current it carries is  I = 3.91 \ A

Generally the magnitude of the magnetic field is mathematically represented as

           B = \frac{\mu_o *  N  * I}{L}

Here  \mu_o  is the permeability of free space with value  \mu_o = 4\pi *10^{-7} \ N/A^2

=>      B = \frac{  4\pi * 10^{-7} * 1740  * 3.91}{0.133}  

=>      B = 0.0643 \ T  

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