Answer:
y = y₀ / 4
Explanation:
In a double slit experiment the constructive interference lines are given by
d sin θ = m λ
if we use trigonometry
tan θ = y / L
as in these experiments the angles are very small
tan θ = sin θ /cos θ = sin θ
we substitute
sin θ = y / L
d y / L = m λ
let's use a subscript "o" for the initial values
I = m λ₀ L /d₀
They ask us to decrease the wavelength by 2
λ = λ₀ / 2
the distance in the slit is increased by a factor of two
d = 2 d₀
we substitute
2d₀ y/L = m λ₀/2
y = m λ₀ L/d₀ ¼
y = y₀ / 4
Answer:
Explanation:
volume of each raft = cross sectional area x length
= π r² x L , r is radius of raft and L is length
= 3.14 x .19 x .19 x 6.1
= .69 m³
total volume of 10 raft = 6.9 m³
mass of raft = 6.9 x 600
= 4140 kg
Let no of person which can be balanced be n
weight of n person = 70 n
total weight = 70 n + 4140 kg
buoyant force when whole of raft is submerged in water
= volume of displaced water x density of water x g
= total volume of raft x density of water x g
= 6.9 x 1000 x g
for equilibrium
buoyant force = total weight of raft and persons
6.9 x 1000 x g = (70 n + 4140 ) x g
6900 = 4140 + 70n
70n = 2760
n = 40 approx
Answer:
Height reached will be 28.35 m
Explanation:
Here we can use the work energy theorem to find the maximum height
As we know by work energy theorem
Work done by gravity + work done by friction = change in kinetic energy
now we will have
so here the height raised by the stone will be 28.35 m from the ground after projection in upward direction
Answer:
For starters, “dark side” is a misnomer. The far side may be constantly facing away from Earth, but as it orbits the Earth it sometimes faces the sun just as the bright side does. Thus the far side is subject to the same day/night temperature extremes as the side facing Earth.
Explanation:
Answer: KE=0.5*m*v2
Explanation: hope this helps!!!