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Lilit [14]
2 years ago
8

Two friends push with great force against a rock. The forces are equally strong but in opposite directions. A heavy box rests on

top of the rock. Answer these questions about the motion of the rock. Assume that the rock is light enough for either friend to carry.
Does the rock move? If so, in which direction does it move? Explain.
Chemistry
2 answers:
jolli1 [7]2 years ago
8 0
The rock wouldn’t move
Dmitry_Shevchenko [17]2 years ago
6 0
The rock doesn’t move. This is because there is an equal force on each side.
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1 point
levacccp [35]

Answer:

A pure substance has a definite chemical composition

4 0
3 years ago
Why do scientists make hypothesis
Sergeeva-Olga [200]
Scientists make hypothesis in order to make an educated guess on the outcome of the experiment.
8 0
3 years ago
Read 2 more answers
AgI + KNO3<br>What type of reaction is this?
emmasim [6.3K]

Answer:

double replacement

Explanation:

4 0
3 years ago
A 112. 6 g mass of unknown material is submersed in 102 ml of water to yield a final volume of 126 ml. What is the apparent dens
skad [1K]

The density of the unknown material is 0.213 ml/g

<h3>Apparent density of the unknown material</h3>

The apparent density of the unknown material is calculated as follows;

Volume of the unknown substance = 126 ml - 102 ml = 24 ml

Density of the unknown substance = mass/volume

Density of the unknown substance =  24 ml / 112.6 g

Density of the unknown substance = 0.213 ml/g

Thus, the density of the unknown material is 0.213 ml/g

Learn more about density here; brainly.com/question/6838128

#SPJ1                          

4 0
1 year ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
2 years ago
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