Answer:
Explanation:
If Ig be moment of inertia about an axis through centre of mass and I be moment of inertia through any other axis parallel to earlier axis , then according to theory of parallel axis ,
I = Ig + Md²
where M is mass of the body and d is distance between two parallel axis.
So I is greater than Ig.
At a depth of 10 m, the manatee's neutral buoyancy keeps it at the same level in water as if there were no air inside its lungs. However, because more air is now contained in the manatee's lungs than before it dove, its weight increases by 9.81 kg and therefore it accelerates downwards (due to momentum). This downward acceleration continues until equilibrium is reached and then ceases due to gravity pulling on both objects equally.
As a result, the manatee now becomes negatively buoyant and must rise to compensate.
<h3>What does it mean when something has neutral buoyancy?</h3>
When something has neutral buoyancy, it is not affected by the weight of anything above or below it.
This means that objects with neutral buoyancy will stay in place regardless of how high or low they are located in a liquid medium.
Examples of things with neutral buoyancy include air balloons and swimming caps.
To learn more about neutral buoyancy, visit:
brainly.com/question/2170899
#SPJ4
Answer:
The velocity of the second car when it passes the first car is 40 m/s
Explanation:
The position and velocity of the cars is given by the following equations:
x = x0 + v0 · t + 1/2 · a · t²
v = v0 + a · t
Where:
x = position at time t
x0 = initial position
v0 = initial velocity
t = time
a = acceleration
v = velocity at time t
If the velocity is constant, then a = 0 and x = x0 + v · t
When the second car passes the first car, the position of both cars is the same:
x first car = x second car
x0 + v · t = x0 + v0 · t + 1/2 · a · t² (x0 = 0 and v0 = 0)
v · t = 1/2 · a · t²
2 · v /a = t
2 · 20 m/s / 2.0 m/s² = t
t = 20 s
Using the equation of velocity, we can calculate the velocity of the second car at t = 20 s
v = v0 + a · t
v = 0 m/s + 2.0 m/s² · 20 s = 40 m/s
The velocity of the second car when it passes the first car is 40 m/s
Is is there for 19 years.
Complete Question
A toroidal solenoid has 590 turns, cross-sectional area 6.20 cm^2 , and mean radius 5.00 cm .
Part A. Calculate the coil's self-inductance.
Part B. If the current decreases uniformly from 5.00 A to 2.00 A in 3.00 ms, calculate the self-induced emf in the coil.
Part C. The current is directed from terminal a of the coil to terminal b. Is the direction of the induced emf from a to b or from b to a?
Answer:
Part A
Part B
Part C
From terminal a to terminal b
Explanation:
From the question we are told that
The number of turns is
The cross-sectional area is
The radius is
Generally the coils self -inductance is mathematically represented as
Where is the permeability of free space with value
substituting values
Considering the Part B
Initial current is
Current at time t is
The time taken is
The self-induced emf is mathematically evaluated as
=>
substituting values
The direction of the induced emf is from a to b because according to Lenz's law the induced emf moves in the same direction as the current