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soldier1979 [14.2K]
3 years ago
11

Look up the active ingredient in baking soda. Write a molecular and net ionic equation when that active ingredient is mixed with

acetic acid. Take note of what blanks have charges to know where to input each chemical. (In the equation input subscripted values as normal text. i.e. water would be H2O)
Chemistry
1 answer:
Volgvan3 years ago
6 0

Answer:

The active ingredients in baking soda (NaHCO3) are

Na^+ and HCO3^-

when Baking soda reacts with Acetic acid

Molecular equation

 NaHCO3(aq) + CH3COOH(aq) → Na(CH3COO)(aq) + CO2(g) +H2O(l)

Ionic equation

Na^+ + HCO3^-  + CH3COOH →   Na^+ + CH3COO^-  +CO2 + H2O

as Na^+ is present on both sides so it will cancel out and the net ionic equation will be

HCO3^-(aq) + CH3COOH(aq) → CH3COO^-(aq) + CO2(g) + H2O(l)

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When may a scientific theory be revised?
Anika [276]

Answer:

it can be revised at any time.

Explanation:

6 0
3 years ago
Read 2 more answers
Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.
Cerrena [4.2K]

Answer:

Answer :

The total pressure inside the cylinder is, 6.7 atm

The mole fraction of N_2 in the mixture is, 0.52

Solution :

First we have to calculate the total pressure inside the cylinder.

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

P_T=p_{N_2}+p_{O_2}+p_{Ar}+p_{He}

Now put all the given values is expression, we get the total pressure inside the cylinder.

P_T=3.5+2.8+0.25+0.15=6.7atm

Now we have to calculate the mole fraction of N_2 in the mixture.

Formula used :

pN_2=XN_2 x P_T

where,

P_T = total pressure = 6.7 atm

pN_2 = partial pressure of nitrogen gas = 3.5 atm

XN_2 = mole fraction of nitrogen gas = ?

Now put all the given values in the above formula, we get

3.5atm=XN_2 x 6.7atm

XN_2=0.52

Therefore, the total pressure inside the cylinder is, 6.7 atm and the mole fraction of N_2 in the mixture is, 0.52

Hope it helps answer the question:)

5 0
3 years ago
What would be the oxidation number of the atoms in these compounds?
sashaice [31]

Answer:

Oxidation state] is defined as the charge an atom might be imagined to have when electrons are counted according to an agreed-upon set of rules:

The oxidation state of a free element (uncombined element) is zero for a simple (monoatomic) ion, the oxidation state is equal to the net charge on the ion.

Hydrogen has an oxidation state of 1 and oxygen has an oxidation state of −2 when they are present in most compounds. (Exceptions to this are that hydrogen has an oxidation state of −1 in hydrides of active metals, e.g. LiH, and oxygen has an oxidation state of −1 in peroxides, e.g. H2O2 the algebraic sum of oxidation states of all atoms in a neutral molecule must be zero, while in ions the algebraic sum of the oxidation states of the constituent atoms must be equal to the charge on the ion.

The same is written in my textbook. But how am I supposed to find the ox. number of an atom, which is in compound like K2UO4?

8 0
3 years ago
Anyone know this please and thank you
Bas_tet [7]

Answer:

The correct answer is a hypothesis.

8 0
1 year ago
I need help with this :(
olga2289 [7]

Answer: 79.6 g

mwof 02 is 16 and mw of H2O is 18.

6 0
2 years ago
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