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iogann1982 [59]

3 years ago

10

When a 0.622 kg basketball hits the floor, its velocity changes from 4.23 m/s down to 3.85 m/s up. If the ball was in contact wi

th the floor for 0.0266 s, how much force did the floor exert on it?

1 answer:

SVEN [57.7K]3 years ago

4 0

when the ball hits the floor and bounces back the momentum of the ball changes.

the rate of change of momentum is the force exerted by the floor on it.

the equation for the force exerted is

f = rate of change of momentum

$f = \frac{mv - mu}{t}$

v is the final velocity which is - 3.85 m/s

u is initial velocity - 4.23 m/s

m = 0.622 kg

time is the impact time of the ball in contact with the floor - 0.0266 s

substituting the values

$f = \frac{0.622 kg (3.85 m/s - (-)4.23 m/s)}{0.0266}$

since the ball is going down, we take that as negative and ball going upwards as positive.

f = 189 N

the force exerted from the floor is 189 N

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If it takes 150 n of force to accelerate an object at 30 m/s what is the mass of the object

iris [78.8K]

F = ma.

Note Force should be = 150 N. Acceleration = 30 m/s2 ( Am presuming for your question you meant to write 30m/s2 and not 30m/s as you wrote)

150 = m ( 30)

150/30 = m.

5 = m

Mass of the object = 5 Kg.

3 0

3 years ago

A person absentmindedly walks off the edge of a tall cliff. They will fall 50 m into either

kifflom [539]

The man can survive, and he lands 12.1 m from the base of the cliff (into the lake)

Explanation:

The motion of the person is equivalent to the motion of a projectile, which consists of two separate motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion, to find the time it take for the person to reach the ground level. We can use the following suvat equation:

$s=ut+\frac{1}{2}gt^2$

where

s = 50 m is the vertical distance covered (the height of the cliff)

u = 0 is the initial vertical velocity

$g=9.8 m/s^2$ is the acceleration of gravity

t is the time of flight

Solving for t,

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(50)}{9.8}}=3.19 s$

The person moved horizontally at a constant speed of

$v_x = 3.8 m/s$

So, the horizontal distance covered by the man during his flight will be

$d_x = v_x t = (3.8)(3.19)=12.1 m$

So, the man will land on the lake (which starts from 12 m), so he can survive.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

8 0

3 years ago

What is characteristic of both sound waves and electromagnetic waves?

Leno4ka [110]

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4 0

4 years ago

HELP ME ASAP!!!! PIC IS DOWN BELOW!

vagabundo [1.1K]

I think it is B Because it sounds like the best choice

7 0

3 years ago

Read 2 more answers

An interference pattern is produced by light with a wavelength 550 nm from a distant source incident on two identical parallel s

ad-work [718]

Answer:

a

$\theta = 0.0022 rad$

b

$I = 0.000304 I_o$

Explanation:

From the question we are told that

The wavelength of the light is $\lambda = 550 \ nm = 550 *10^{-9} \ m$

The distance of the slit separation is $d = 0.500 \ mm = 5.0 *10^{-4} \ m$

Generally the condition for two slit interference is

$dsin \theta = m \lambda$

Where m is the order which is given from the question as m = 2

=> $\theta = sin ^{-1} [\frac{m \lambda}{d} ]$

substituting values

$\theta = 0.0022 rad$

Now on the second question

The distance of separation of the slit is

$d = 0.300 \ mm = 3.0 *10^{-4} \ m$

The intensity at the the angular position in part "a" is mathematically evaluated as

$I = I_o [\frac{sin \beta}{\beta} ]^2$

Where $\beta$ is mathematically evaluated as

$\beta = \frac{\pi * d * sin(\theta )}{\lambda }$

substituting values

$\beta = \frac{3.142 * 3*10^{-4} * sin(0.0022 )}{550 *10^{-9} }$

$\beta = 0.06581$

So the intensity is

$I = I_o [\frac{sin (0.06581)}{0.06581} ]^2$

$I = 0.000304 I_o$

3 0

3 years ago