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WARRIOR [948]
3 years ago
8

A scale reads 184 N when a piece of copper is hanging from it. What does it read (in N) when it is lowered so that the copper is

submerged in water?
Physics
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

  163 N

Explanation:

The density of copper is about 8.96. The ratio of the weight in water to the weight in air is about 1-1/ρ, so is about 0.8884.

  0.8884 × 184 N ≈ 163 N

The submerged weight is about 163 N.

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A lever has an input arm 50 centimeters long and an output arm 40 centimeters long. What is the mechanical advantage of the leve
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45

Explanation:

well 45

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3 years ago
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At an accident scene on a level road, investigators measure a car’s skid mark to be 88 m long. The accident occurred on a rainy
Oduvanchick [21]

Answer:

The the speed of the car is 26.91 m/s.

Explanation:

Given that,

distance d = 88 m

Kinetic friction = 0.42

We need to calculate the the speed of the car

Using  the work-energy principle

work done = change in kinetic energy

W=\Delta K.E

\mu\ mg\times d=\dfrac{1}{2}mv^2

v^2=2\mu g d

Put the value into the formula

v=\sqrt{2\times0.42\times9.8\times88}

v=26.91\ m/s

Hence, The the speed of the car is 26.91 m/s.

3 0
3 years ago
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Two large, plastic tubs were filled with soil The soil was shaped to create a mound in each tub. The starting height of each mou
shutvik [7]

Answer:

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6 0
2 years ago
if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

Therefore, the mutual force between the two point charges is 319.64 N

4 0
3 years ago
an engine has been design to work between source and the sink at temperature 177 degree Celsius and 27 degree Celsius respective
irina [24]

<u>Given data</u>

Source temperature (T₁) = 177°C = 177+273 = 450 K

Sink temperature (T₂) = 27°C = 27+273 = 300 K

Energy input (Q₁) = 3600 J ,

Work done = ?

                We know that, efficiency (η) = Net work done ÷ Heat supplied

                                                           η =   W ÷ Q₁  

                                                           W = η × Q₁

               First determine the efficiency ( η ) = ?

                                Also, we know that ( η ) = (T₁ - T₂) ÷ (T₁)

                                                                        = 33.3% = 0.333

               Now, Work done is W = η × Q₁

                                                    = 0.33 × 3600

                                                 <em>  W = 1188 J</em>

<em>Work done by the engine is 1188 J</em>

4 0
3 years ago
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