A projectile fired upward from the Earth's surface will usually slow down, come momentarily to rest, and return to Earth. For a certain initial speed, however it will move upward forever, with its speed gradually decreasing to zero just as its distance from Earth approaches infinity. The initial speed for this case is called escape velocity. You can find the escape velocity v for the Earth or any other planet from which a projectile might be launched using conservation of energy. The projectile of mass m leaves the surface of the body of mass M and radius R with a kinetic energy Ki = mv²/2 and potential energy Ui = -GMm/R. When the projectile reaches infinity, it has zero potential energy and zero kinetic energy since we are seeking the minimum speed for escape. Thus Uf = 0 and Kf = 0. And from conservation of energy,
Ki + Ui = Kf + Uf
mv²/2 -GMm/R = 0
∴ v = √(2GM/R)
This is the expression for escape velocity.
Answer:
To find the circumference (orbit) of an object, you use Pi x Diameter.
As you have the circumference of B, you divide it by Pi to get the Diameter.
So 120 divided by 3.141592654 = 38.2 minutes for the Diameter.
As' radius and Diameter will be 3x greater than B.
38.2 x 3 = 114.6
To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes
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Answer:
A homopolar motor is a direct current electric motor with two magnetic poles, the conductors of which always cut unidirectional lines of magnetic flux by rotating a conductor around a fixed axis so that the conductor is at right angles to a static magnetic field.
Explanation:
Path 2.
Displacement is the direction and magnitude of an object from its starting point, so path 2 is the direct route you would need to take to find direction and magnitude.
Answer:
c) The slope is not constant and increases with increasing time.
Explanation:
The equation for the position of this particle (starting from rest is)

We can take derivative of this with respect to time t to get the equation of slope:

As time t increase, the slope would increases with time as well.