Since Aaron left the city at 12pm (noon) and needs to be arrive at the next city at 3pm he has exactly 3 hours. Since he is going 65 km/h we need to divide 185 by 65 to find out how long it will take for Aaron to travel 185km.
186 / 65 =
2.86
Aaron will arive at the next city in 2.86 hours meaning he will not arrive late and will arive on time. I hope this helps you :D
Answer:
<h2>50m/s^2</h2>
Explanation:
Step one:
given data
initial velocity u= 0m/s since the ball is at rest
time of contact t= 0.3s
final velocity v=15m/s
Required
acceleration a
from the first law of motion
v=u+at
substitute our given data
15=0+a*0.3
15=0.3a
divide both sides by 0.3
a=15/0.3
a=50m/s
<u>The average acceleration is 50m/s^2</u>
Answer:
<em>The correct difference is 3.44 ft</em>
Explanation:
The correct difference is given as
D=R_A-R_B
D=9.09-5.65
D=3.44 ft
Answer:
k = 200 N/m
Explanation:
given,
mass of the object = 251 g
= 251 x 10⁻³ Kg = 0.251 Kg
distance of tendon stretch = x = 1.23 cm
= 1.23 x 10⁻² = 0.0123 m
using the formula
F = k x
where
k is the force constant of the tendon
F = m g
F = 0.251 x 9.8 = 2.4598 N
2.4598 = k x 0.0123
k = 199.98 N/m
k = 200 N/m
hence, force constant of the tendon is approximately equal to 200 N/m
