A teacher uses a bow and arrow to demonstrate accuracy and precision. she shoots several arrows, aiming at the exact center of the target each time. thedrawing below shows where her arrows hit the target.
<span> The statement that best describes her shots is
</span><span>Her shots were neither accurate nor precise
</span>hope it helps
Two factors that determine whether a molecule is polar are the types of atoms in the molecule and the SHAPE of the molecule.
A polar molecule is a molecule with two opposing charges, one end of the molecule has a partial negative charge while the other end has a partial positive charge. This occurs because the molecule is not totally symmetric. The polarity of a substance is typically determined by the characteristics of its constituent atoms and the shape of the molecule. Polar molecules are usually bent or trigonal in shape.
Answer:
![C_2H_2 (g) + \frac{5}{2}~O_2 (g)\rightarrow 2~CO_2 (g) + H_2O (l)](https://tex.z-dn.net/?f=C_2H_2%20%28g%29%20%2B%20%5Cfrac%7B5%7D%7B2%7D~O_2%20%28g%29%5Crightarrow%202~CO_2%20%28g%29%20%2B%20H_2O%20%28l%29)
Explanation:
Acetylene is an organic compound consisting of only carbon and hydrogen atoms, also known as a pure hydrocarbon.
Every hydrocarbon might undergo either an incomplete or a complete combustion. In an incomplete combustion, carbon monoxide is produced along with water, while in a complete combustion, there's enough oxygen to oxidize the resultant carbon monoxide to carbon dioxide.
In a complete combustion of acetylene, it reacts with oxygen to produce carbon dioxide and water:
![C_2H_2 (g) + \frac{5}{2}~O_2 (g)\rightarrow 2~CO_2 (g) + H_2O (l)](https://tex.z-dn.net/?f=C_2H_2%20%28g%29%20%2B%20%5Cfrac%7B5%7D%7B2%7D~O_2%20%28g%29%5Crightarrow%202~CO_2%20%28g%29%20%2B%20H_2O%20%28l%29)
Answer:
![Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)](https://tex.z-dn.net/?f=Ag%5E%2B%28aq%29%2BCl%5E-%28aq%29%5Crightarrow%20AgCl%28s%29)
Explanation:
Hello!
In this case, since the net ionic equations are ionic representations of the molecular equation in which the spectator ions (those at both reactants and products sides) are cancelled out, we first write the complete ionic equation for this reaction, considering that the solid silver chloride is not ionized due to its precipitation:
![Ag^+(aq)+NO_3^-(aq)+Na^+(aq)+Cl^-(aq)\rightarrow AgCl(s)+Na^+(aq)+NO_3^-(aq)](https://tex.z-dn.net/?f=Ag%5E%2B%28aq%29%2BNO_3%5E-%28aq%29%2BNa%5E%2B%28aq%29%2BCl%5E-%28aq%29%5Crightarrow%20AgCl%28s%29%2BNa%5E%2B%28aq%29%2BNO_3%5E-%28aq%29)
Whereas the nitrate and sodium ions are cancelled out for the aforementioned reason as they are the spectator ions, to obtain:
![Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)](https://tex.z-dn.net/?f=Ag%5E%2B%28aq%29%2BCl%5E-%28aq%29%5Crightarrow%20AgCl%28s%29)
Which is the required net ionic equation.
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Answer:
When pH = pKa, the ionizable compound in question (either acid or base) will be half protonated and half deprotonated
Explanation:
A convenient way of expressing the relative strength of an acid is by the value of its pKa, which makes it easy to see in small changes in pKa the changes associated with large variations in Ka. Small pKa values are equivalent to large Ka (dissociation constant) values, and as pKa decreases, the strength of the acid increases.
An acid will be stronger the lower its pKa and in a base it happens the other way around, which is stronger the higher its pKa.
Those dissociation constants are not fixed, they depend on other variables. For example, the dissociation constant changes at different temperatures. However, it maintains its value at the same temperature, before changes in the concentration of any of the species or even under the action of a catalyst.