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Nina [5.8K]
3 years ago
11

If 2 objects have the same momentum which statement is true

Physics
2 answers:
rewona [7]3 years ago
8 0

The correct answer is B

Soloha48 [4]3 years ago
7 0

Answer:

correct answer is option B(The product mass X velocity is the same for both)

Explanation:

Momentum:

momentum of a body is defined as the product of mass and velocity with which body is moving.

Momentum of a body of mass m and which is moving with velocity v is given as

p=m\times v

if two bodies have same momentum it means the product of mass and velocity is same for both.

If two bodies have dfferent masses and if they are moving with different velocities then also they may have same momentum.

for example,

first body has mass 4kg and it is moving with 10m/s velocity

then its momentum is p_{1} =4kg\times 10ms^{-1}

p_{1} =40kgms^{-1}

similarly if second body has mass 2kg and if it is moving with 20m/s velocity

then its momentum is p_{2} =2kg\times 20ms^{-1}

p_{2} =40kgms^{-1}

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Einstein's theory determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels.
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3 years ago
The escape velocity at the surface of Earth is approximately 11 km/s. What is the mass, in units of ME (the mass of the Earth),
SVETLANKA909090 [29]

Answer:11 km/s

Explanation:

Given

Escape velocity at the surface of earth is 11 km/s

Escape velocity is given by

V_e=\sqrt{\frac{2GM}{R}}

Escape velocity at the surface of earth

11=\sqrt{\frac{2GM}{R}}--------------------1

If Escape velocity is three times and the radius is also the three times

V_e_2=\sqrt{\frac{2G(3M)}{3R}}

V_e_2=\sqrt{\frac{2GM}{R}}=V_e

i.e. V_e_2=11 km/s

5 0
2 years ago
How much would you have to eat for your appendix to explode ? I ate so much on thanksgiving and i need to know i’m very scared
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Answer:

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6 0
3 years ago
You are trying to overhear a juicy conversation, but from your distance of 20.0 m , it sounds like only an average whisper of 30
12345 [234]

Answer:

r₂ = 0.2 m

Explanation:

given,

distance = 20 m

sound of average whisper = 30 dB

distance moved closer = ?

new frequency = 80 dB

using formula

\beta = 10 log(\dfrac{I_1}{I_0})

   I₀ = 10⁻¹² W/m²

now,

30 = 10 log(\dfrac{I_1}{10^{-12}})

\dfrac{I_1}{10^{-12}}= 10^3

I_1= 10^{-8}\ W/m^2

to hear the whisper sound = 80 dB

80 = 10 log(\dfrac{I_2}{10^{-12}})

\dfrac{I_2}{10^{-12}}= 10^8

I_2= 10^{-4}\ W/m^2

we know intensity of sound is inversely proportional to square of distances

\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}

\dfrac{10^{-8}}{10^{-4}}=\dfrac{r_2^2}{20^2}

10^{-4}=\dfrac{r_2^2}{20^2}

  r₂ = 0.2 m

6 0
3 years ago
At which angle must a laser beam enter the water for no refraction to occur?
abruzzese [7]

Light that enters the new medium <em>perpendicular to the surface</em> keeps sailing straight through the new medium unrefracted (in the same direction).

Perpendicular to the surface is the "normal" to the surface. So the angle of incidence (angle between the laser and the normal) is zero, and the law of refraction (just like the law of reflection) predicts an angle of zero between the normal and the refracted (or the reflected) beam.

Moral of the story:  If you want your laser to keep going in the same direction after it enters the water, or to bounce back in the same direction it came from when it hits the mirror, then shoot it <em>straight on</em> to the surface, perpendicular to it.

5 0
3 years ago
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