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Nina [5.8K]
3 years ago
11

If 2 objects have the same momentum which statement is true

Physics
2 answers:
rewona [7]3 years ago
8 0

The correct answer is B

Soloha48 [4]3 years ago
7 0

Answer:

correct answer is option B(The product mass X velocity is the same for both)

Explanation:

Momentum:

momentum of a body is defined as the product of mass and velocity with which body is moving.

Momentum of a body of mass m and which is moving with velocity v is given as

p=m\times v

if two bodies have same momentum it means the product of mass and velocity is same for both.

If two bodies have dfferent masses and if they are moving with different velocities then also they may have same momentum.

for example,

first body has mass 4kg and it is moving with 10m/s velocity

then its momentum is p_{1} =4kg\times 10ms^{-1}

p_{1} =40kgms^{-1}

similarly if second body has mass 2kg and if it is moving with 20m/s velocity

then its momentum is p_{2} =2kg\times 20ms^{-1}

p_{2} =40kgms^{-1}

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4 0
3 years ago
Use Hooke's Law, which states that the distance a spring stretches (or compresses) from its natural, or equilibrium, length vari
Phantasy [73]

Answer:

706.68 N

Explanation:

By Hooke's law,

F = ke

k=\dfrac{F}{e}

Using the values in the question,

k=\dfrac{265\text{ N}}{0.15 \text{ m}}=1766.7\text{ N/m}

When e = 0.4 m,

F = 1766.7\text{ N/m}\times0.4\text{ m}=706.68\text{ N}

6 0
3 years ago
What is the goal of the scientific method
IgorLugansk [536]

Answer:

Regardless of how the steps are documented, the goal of scientific method is to gather data that will validate or invalidate a cause and effect relationship.

Hope this helped!!!

7 0
3 years ago
Which sentence states Newton’s third law?
Katyanochek1 [597]
Each object exerts a force equal to and in the opposite direction of the other.
8 0
3 years ago
A 3.00N rock is thrown vertically into the air from the ground. At h=15.0m, v=25m/s upward. Use the work-energy theorem to find
butalik [34]

Answer:

so initial speed of the rock is 30.32 m/s

correct answer is b. 30.3 m/s

Explanation:

given data

h = 15.0m

v = 25m/s

weight of the rock m = 3.00N  

solution

we use here work-energy theorem that is express as here

work = change in the kinetic energy    ..............................1

so it can be written as

work = force × distance     ...................2

and

KE is express as

K.E = 0.5 × m × v²  

and it can be written as

F × d = 0.5 × m × (vf)² - (vi)²      ......................3

here

m is mass and vi and vf is initial and final velocity

F = mg = m  (-9.8)  , d = 15 m and v{f} = 25 m/s

so put value in equation 3 we get

m  (-9.8) × 15 = 0.5 × m × (25)² - (vi)²

solve it we get

(vi)² =  919

vi = 30.32 m/s

so initial speed of the rock is 30.32 m/s

5 0
3 years ago
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