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pogonyaev
3 years ago
7

Help please with question 2bii The one that starts with calculate the average ....

Physics
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

add text fully or atleast add book name edition . solution is in picture.  chk pictures ignore b part

Explanation:

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An initially uncharged 3.47-μF capacitor and a 6.43-kΩ resistor are connected in series to a 1.50-V battery that has negligible
harkovskaia [24]

Answer: a) io=233.28 A ( initial current); b) τ=R*C= 22.31 ms; c) 81.7 ms

Explanation:  In order to explain this problem we have to use, the formule for the variation of the current in a RC circuit:

I(t)=io*Exp(-t/τ)

and also we consider that io=V/R=(1.5/6.43*10^3)

=233.28 A

then the time constant for the RC circuit is τ=R*C=6.43*10^3*3.47*10^-6

=22.31 ms

Finally the time to reduce the current to 2.57% of its initial value is obtained from:

I(t)=io*Exp(-t/τ)  for I(t)/io=0.0257=Exp(-t/τ) then

ln(0.0257)*τ =-t

t=-ln(0.0257)*τ=81.68 ms

3 0
3 years ago
PLEASE HELPPPP !!!! Scientific investigations must be well ____ to be sure the data collected will help answer the scientists qu
konstantin123 [22]
Answer-

Analyzed or conducted

Hope this helped
3 0
2 years ago
Which equation states Newton's second law?
Delicious77 [7]

Answer:

It's actually

F=ma

Force=Mass x Acceleration

So...when we inverse it..

It becomes:

B. a= F/m

5 0
3 years ago
Which electromagnetic has the shortest wavelength?.
Marina CMI [18]

Answer:

Gamma rays

Explanation:

7 0
2 years ago
The brakes on your automobile are capable of creating a deceleration of 4.6 m/s^2. If you are going 114 km/h and suddenly see a
drek231 [11]

Answer:

The minimum time to get the car under max. speed limit of 79 km/h is 2.11 seconds.

Explanation:

a=\frac{V_f-V_0}{t}

isolating "t" from this equation:

t=\frac{V_f-V_0}{a}

Where:

a=-4.6m/s^2 (negative because is decelerating)

V_f= 79 km/h

V_0= 114 km/h

First we must convert velocity from km/h to m/s to be consistent with units.

79\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{79*1000}{3600}=21.94 m/s

114\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{114*1000}{3600}=31.67 m/s

So;

t=\frac{V_f-V_0}{a}=\frac{21.94 m/s-31.66m/s}{-4.6 m/s^2}=2.11 s

7 0
3 years ago
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