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kondaur [170]
3 years ago
9

Compute the reactance of a 0.450 H inductor at the frequency of 60.0 Hz. Express your answer in ohms.

Chemistry
1 answer:
vlada-n [284]3 years ago
7 0

Answer:

169.67Ω

Explanation:

This question is asking for the inductive reactance, which is calculated as follows:

X(L) = 2πfL

Where;

X(L) = inductive reactance (Ω)

f = frequency (Hz)

π = 3.142

L = inductance (Henry)

Given the information provided, f = 60Hz, L = 0.450H

X(L) = 2πfL

X(L) = 2 × 3.142 × 60 × 0.450

X(L) = 6.284 × 60 × 0.450

X(L) = 6.284 × 27

X(L) = 169.668

X(L) = 169.67Ω

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Answer:

The volume of the solution must be increased to 71.429 millimeters by adding 66.359 millimeters of solute to reduce molarity from 6.82 M to 0.49 M.

Explanation:

The molarity is a unit used for solution that is equivalent to the amount of moles of solute per unit volume of solution. That is:

M = \frac{n_{st}}{V_{sol}}

Where:

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To reduce the molarity of the solution, more millimeters of solvent should be added. Firstly, the amount of moles of acetic acid inside the 6.82 M solution needs to be determined (M_{o} = 6.82\,M and V_{sol} = 5.07\times 10^{-3}\,L):

n_{st} = M_{o}\cdot V_{sol}

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V_{sol} = \frac{0.035\,mol}{0.49\,M}

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V_{sol} = 71.429\,mL (1 L = 1000 mL)

The amount of solvent needed to dilute the solution is:

\Delta V_{sol} = 71.429\times 10^{-3}\,L - 5.07\times 10^{-3}\,L

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