Answer:
Coat new O-rings (D) with silicone oil or polyalkyleneglycol (PAG) oil, and pull them on the injectors.
Answer:
V = 0.30787 m³/s
m = 2.6963 kg/s
v2 = 0.3705 m³/s
v2 = 6.017 m/s
Explanation:
given data
diameter = 28 cm
steadily =200 kPa
temperature = 20°C
velocity = 5 m/s
solution
we know mass flow rate is
m = ρ A v
floe rate V = Av
m = ρ V
flow rate = V =
V = Av = ![\frac{\pi}{4} * d^2 * v1](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2A%20d%5E2%20%2A%20v1)
V = ![\frac{\pi}{4} * 0.28^2 * 5](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2A%200.28%5E2%20%2A%205)
V = 0.30787 m³/s
and
mass flow rate of the refrigerant is
m = ρ A v
m = ρ V
m =
= ![\frac{0.30787}{0.11418}](https://tex.z-dn.net/?f=%5Cfrac%7B0.30787%7D%7B0.11418%7D)
m = 2.6963 kg/s
and
velocity and volume flow rate at exit
velocity = mass × v
v2 = 2.6963 × 0.13741 = 0.3705 m³/s
and
v2 = A2×v2
v2 = ![\frac{v2}{A2}](https://tex.z-dn.net/?f=%5Cfrac%7Bv2%7D%7BA2%7D)
v2 = ![\frac{0.3705}{\frac{\pi}{4} * 0.28^2}](https://tex.z-dn.net/?f=%5Cfrac%7B0.3705%7D%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2A%200.28%5E2%7D)
v2 = 6.017 m/s
Answer:
7.615 kW
Explanation:
Solution in pen paper form in the attachment section
Answer:
$7,778.35
Explanation:
At year 3, the final payment of the remaining balance is equal to the present worth P of the last three payments.
First, calculate the uniform payments A:
A = 12000(A/P, 4%, 5)
= 12000(0.2246) = 2695.2 (from the calculator)
Then take the last three payments as its own cash flow.
To calculate the new P:
P = 2695.2 + 2695.2(P/A, 4%, 2) = 2695.2 + 2695.2(1.886) = 7778.35
Therefore, the final payment is $7,778.35
Answer:
4.5kg/min
Explanation:
Given parameters
![T_1 = 32^0 C, m_1 = 3 kg/min, T_2 = 7^0 C ,T_3 = 17^0](https://tex.z-dn.net/?f=T_1%20%3D%2032%5E0%20C%2C%20%20m_1%20%3D%203%20kg%2Fmin%2C%20T_2%20%3D%207%5E0%20C%20%2CT_3%20%3D%2017%5E0)
if we take
The mass flow rate of the second stream = ![m_2(kg/min)](https://tex.z-dn.net/?f=m_2%28kg%2Fmin%29)
The mass flow rate of mixed exit stream = ![m_3 (kg/min)](https://tex.z-dn.net/?f=m_3%20%28kg%2Fmin%29)
Now from mass conservation
![m_3 = m_2 + m_1](https://tex.z-dn.net/?f=m_3%20%3D%20m_2%20%2B%20m_1)
![m_3 = m_2 + 3 (kg/min)](https://tex.z-dn.net/?f=m_3%20%3D%20m_2%20%2B%203%20%28kg%2Fmin%29)
The temperature of the mixed exit stream given as
![T_3m_3 = T_2m_2 +T_1m_1\\\\17 ( 3 + m_2) = 7 \times m_2 + 32 \times 3\\\\51 + 17 m_2 = 7 m_2 + 96\\\\10 m_2 = 96 - 51\\\\m_2 = 4.5 kg/min\\\\\\\\](https://tex.z-dn.net/?f=T_3m_3%20%3D%20T_2m_2%20%2BT_1m_1%5C%5C%5C%5C17%20%28%203%20%2B%20m_2%29%20%3D%207%20%5Ctimes%20m_2%20%2B%2032%20%5Ctimes%203%5C%5C%5C%5C51%20%2B%2017%20m_2%20%3D%207%20m_2%20%2B%2096%5C%5C%5C%5C10%20m_2%20%3D%2096%20-%2051%5C%5C%5C%5Cm_2%20%3D%204.5%20kg%2Fmin%5C%5C%5C%5C%5C%5C%5C%5C)
Therefore the mass flow rate of second stream will be 4.5 kg/min.