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r-ruslan [8.4K]
3 years ago
10

A woman is conquering her fear of heights by going bungee jumping. She has a mass of 90 kg. She falls from the tower for a few s

econds before the bungee cord begins pulling back on her with a force of 500 N. What will the magnitude of her acceleration be after the bungee cord begins pulling on her
Physics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

Explanation:

weight of woman acting downwards = 90 x 10 = 900 N

force by bungee cord in upward direction = 500 N

net force = 900 - 500 = 400 N in downward direction

acceleration in downward direction

= 400 / 90

= 4.44 m /s²

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The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o
N76 [4]

Frequency = (speed) / (wavelength)

Frequency = (331 m/s) / (0.6 m) = 551.7 Hz
3 0
2 years ago
Superman is flying 54.5 m/s when he sees
Nady [450]

348.34 m/s. When Superman reaches the train, his final velocity will be 348.34 m/s.

To solve this problem, we are going to use the kinematics equations for constant aceleration. The key for this problem are the equations d=v_{0} t+\frac{at^{2} }{2} and v_{f} =v_{0} +at where d is distance, v_{0} is the initial velocity, v_{f} is the final velocity, t is time, and a is aceleration.

Superman's initial velocity is v_{0}=54.5\frac{m}{s}, and he will have to cover a distance d = 850m in a time t = 4.22s. Since we know d, v_{0} and t, we have to find the aceleration a in order to find v_{f}.

From the equation d=v_{0} t+\frac{at^{2} }{2} we have to clear a, getting the equation as follows: a=\frac{2(d-v_{0}t) }{t^{2} }.

Substituting the values:

a=\frac{2(850m-54.5\frac{m}{s}.4.22s) }{(4.22s)^{2}}=69.63\frac{m}{s^{2}}

To find v_{f} we use the equation v_{f} =v_{0} +at.

Substituting the values:

v_{f} =54.5\frac{m}{s} +(69.63\frac{m}{s^{2}}.4.22s)=348.34\frac{m}{s}

5 0
3 years ago
An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirro
svet-max [94.6K]
 We can rearrange the mirror equation before plugging our values in. 
1/p = 1/f - 1/q. 
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1/p = 4/40cm - 1/40cm = 3/40cm
40cm=3p  <-- cross multiplication
13.33cm = p

Now that we have the value of p, we can plug it into the magnification equation.

M=-16/13.33=1.2
1.2=h'/8cm
9.6=h'

So the height of the image produced by the mirror is 9.6cm.
6 0
2 years ago
While jumping on a trampoline you calculate that at the highest peak of your jump you have 900 joules of gravitational potential
BabaBlast [244]

Jumping on a trampoline is a classic example of conservation of energy, from potential into kinetic. It also shows Hooke's laws and the spring constant. Furthermore, it verifies and illustrates each of Newton's three laws of motion.

<u>Explanation</u>

When we jump on a trampoline, our body has kinetic energy that changes over time. Our kinetic energy is greatest, just before we hit the trampoline on the way down and when you leave the trampoline surface on the way up. Our kinetic energy is 0 when you reach the height of your jump and begin to descend and when are on the trampoline, about to propel upwards.

Potential energy changes along with kinetic energy. At any time, your total energy is equal to your potential energy plus your kinetic energy. As we go up, the kinetic energy converts into potential energy.

Hooke's law is another form of potential energy. Just as the trampoline is about to propel us up, your kinetic energy is 0 but your potential energy is maximized, even though we are at a minimum height. This is because our potential energy is related to the spring constant and Hooke's Law.

8 0
3 years ago
A car slows down from 80 km/h to 60 km/h in 2 seconds.
Andreyy89

Answer:

please mark brainlist

Explanation:

Initial speed   u=80 km/h=80×185=22.22 m/s

Final speed    v=60 km/h=60×185=16.67 m/s

Using   v=u+at

Or   16.67=22.22+α×5

⟹ a=−1.1 m/s2

6 0
3 years ago
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