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Dvinal [7]
3 years ago
9

Which equation represents the correct net ionic equation for the reaction between Ca(OH)2 and H2SO4?

Chemistry
1 answer:
Georgia [21]3 years ago
7 0

<u>Answer:</u> The correct net ionic equation for the reaction is 2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.  

The balanced molecular equation is:

Ca(OH)_2(aq)+H_2SO_4(aq)\rightarrow CaSO_4(aq)+2H_2O(l)

The complete ionic equation follows:

Ca^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2Ca^{2+}(aq)+SO_4^{2-}(aq)+H_2O(l)

As calcium and sulfate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

Hence, the correct net ionic equation for the reaction is 2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

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Ocean water contains 3.5 % NaCl by mass. What mass of ocean water in grams contains 46.8 g of NaCl?
Luda [366]

Answer:

1.3 kg

Explanation:

Mass of ocean water = mass of NaCl × (mass of ocean water/mass NaCl).

The % NaCl tells us there are 3.5 g NaCl/100 g ocean water or 100 g ocean water/3.5 g NaCl.

Mass of ocean water = 46.8 × (100/3.5)

Mass of ocean water = 46.8 × 28.6

Mass of ocean water = 1300 g = 1.3 kg

<em>Note</em>: The answer can have only <em>two significant figures</em> because that is all you gave for the percentage of NaCl.

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4 years ago
100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}

n=0.38\times 10^{-5}

n = moles of NaCN = \frac{\text {given mass}}{\text {Molar mass}}

0.38\times 10^{-5}=\frac{x}{49g/mol}

x=18.62\times 10^{-5}g

Thus the number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

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