Answer:
Vx = 6.242 x 10raised to power 15
Vy = -6.242 x 10raised to power 15
Explanation:
from E = IVt
but V = IR from ohm's law and Q = It from faraday's first law
I = Q/t
E = Q/t x V x t = QV
hence, E =QV
V = E/Q
Tensile testing provides engineers with the ability to verify and establish material properties related to a specific material.
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This question is incomplete, the missing image in uploaded along this answer below.
Answer:
The required stress is 200 Mpa
Explanation:
Given the data in the question;
diameter D = 12 mm = 12 × 10⁻³ m
Length L = 188 mm = 188 × 10⁻³ m
Poisson's ratio v = 0.34
Reduction in diameter Δd = 0.0105 mm = 0.0105 × 10⁻³ m
The transverse strain will;
εˣ = Δd / D
εˣ = -0.0105 × 10⁻³ / 12 × 10⁻³ m
εˣ = -0.00088
The longitudinal strain will be;
= - ( εˣ / v )
= - ( -0.00088 / 0.34 )
= - ( - 0.002588 )
= 0.0026
Now, Using the values for strain, we get the value of stress from the graph provided in the question, ( first image uploaded below.
From the graph, in the Second image;
The stress is 200 Mpa
Therefore, The required stress is 200 Mpa
Answer:
Explanation:
From the information given:
Life requirement = 40 kh = 40
Speed (N) = 520 rev/min
Reliability goal = 0.9
Radial load = 2600 lbf
To find C10 value by using the formula:
where;
The Weibull parameters include:
∴
Using the above formula:
Recall that:
1 kN = 225 lbf
∴