Answer:
(a) Surface energy is greater than grain boundary energy due to the fact that the bonds of the atoms on the surface are lower than those of the atoms at the grain boundary. The energy is also directly proportional to the number of bonds created.
(b) The energy of a high-angle grain boundary is higher than that of a small-angle grain boundary because the high-angle grain boundary has a higher misalignment and smaller number of bonds than a small-angle grain boundary.
Explanation:
(a) Surface energy is greater than grain boundary energy due to the fact that the bonds of the atoms on the surface are lower than those of the atoms at the grain boundary. The energy is also directly proportional to the number of bonds created.
(b) The energy of a high-angle grain boundary is higher than that of a small-angle grain boundary because the high-angle grain boundary has a higher misalignment and smaller number of bonds than a small-angle grain boundary.
Why 1+12+ Y3 < 1100
Says the state of university Need to purchase 1100 computers in total, we have the following answer on the way top
Explanation:
Anodizing :
Anodizing is the surface protection process from the environment.As we know that due to external environment surfaces get corrodes .By using anodizing process the outer surface of material coated by using different type of coating material.
As the name stand that in the anodizing process there will be anode and oxygen.in this process oxidation of material take place .
Oxides of aluminium and magnesium are stable that is why they anodized by this process.
Explanation:
volume = πR²h/3
= πx35²x50/3
= 192325/3
= 64166.725
number of layers n = 50mm/0.05
n = 1000layers
average volume = 64166.725/1000
= 64.167mm³
average area = 64.167/0.05
= 1283.34mm²
average time = 1283.34/900mm x 0.22
= 6.48
6.48 + 15 seconds
= 21.48 seconds
time required = 1000x21.48
= 21480 seconds
convert to minutes
21480/60
= 358 minutes
21480/3600
= 5.967 hours
Answer:
Temperature on the inside ofthe box
Explanation:
The power of the light bulb is the rate of heat conduction of the bulb, 
The thickness of the wall, L = 1.2 cm = 0.012m
Length of the cube's side, x = 20cm = 0.2 m
The area of the cubical box, A = 6x²
A = 6 * 0.2² = 6 * 0.04
A = 0.24 m²
Temperature of the surrounding, 
Temperature of the inside of the box, 
Coefficient of thermal conductivity, k = 0.8 W/m-K
The formula for the rate of heat conduction is given by:
