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3 years ago

F.R.E.E P.O.I.N.T.S F.R.E.E PO.I.N.T.S

Engineering

2 answers:

grigory [225]3 years ago

7 0

Answer:

yayyy thank you

lol

Explanation:

geniusboy [140]3 years ago

4 0

THANK YOU VERY MUCH I APPRECIATE IT

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Exposure to asbestos dust can cause what condition?

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If you end up breathing asbestos fibers, it can increase the risk of serous diseases. Some examples are lung cancer, mesothelioma and asbestosis. It may also increase your risk for cancers of the digestive system, which includes colon cancer. Asbestos is dangerous when fibers become airborne. That is because once a person ingests or inhales asbestos, the fiber can’t be removable from the body. The fibers can cause irritation and scarring over time if it’s embed into the tissue.

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3 years ago

Hãy trình bày các bộ phận chính trong một bộ điều khiển điện tử (ECU) dùng trên ô tô. Cho biết công dụng của từng thành phần.

mestny [16]

Answer:

sorry but I can't understand this Language.

Explanation:

unable to answer sorry

5 0

3 years ago

Sun of first 1 nayural numbers

marin [14]

Answer:

the answer is

$n(n + 1) \div 2$

n(n+1)/2

4 0

3 years ago

Read 2 more answers

A potential difference of 7.00 V is maintained across a 70.0-Ω resistor for a period of 80.0 s. What total charge passes by a po

Bogdan [553]

Answer:

Explanation:

the potential difference is 7v and resistance is 70 ohms the time period is 80.0s.

formular to calculate the amount of current flow is

I = V/R

v= volatge across

R=resistance in the wire

substituting 7v for V and 70 ohms for R

I = 7/70 = 0.1A

0.1A is the amount of current flow.

Total charge for the time interval is

Q = I Δt

i is the amount of current

t is the time interval

Q = 0.1 * 80 = 8c

4 0

4 years ago

The acceleration of a particle is given by a = 4t – 30, where a is in meters per second squared and t is in seconds. Determine t

mestny [16]

Answer:

The velocity of the particle is given by $v(t) = 2\cdot t^{2}-30\cdot t + 3$ , where $v$ is in meters per second and $t$ is in seconds.

The displacement of the particle is given by $s(t) = \frac{2}{3}\cdot t^{3}-15\cdot t^{2}+3\cdot t -5$ , where $s$ is in meters and $t$ is in seconds.

Explanation:

The acceleration of the particle is given by $a(t) = 4\cdot t -30$ , the expression for velocities are obtained by integration:

Velocity

$v(t) = \int {a(t)} \, dt$

$v(t) = \int {4\cdot t-30} \, dt$

$v(t) = 4\int {t} \, dt -30\int \, dt$

$v(t) = 2\cdot t^{2}-30\cdot t + v_{o}$

Where $v_{o}$ is the initial velocity of the particle, measured in meters per second.

If $t = 0$ and $v(0) = 3$ , then:

$3 = 2\cdot (0)^{2}-30\cdot (0)+v_{o}$

$v_{o} = 3$

The velocity of the particle is given by $v(t) = 2\cdot t^{2}-30\cdot t + 3$ , where $v$ is in meters per second and $t$ is in seconds.

Displacement

$s(t) = \int {v(t)} \, dt$

$s(t) = \int {2\cdot t^{2}-30\cdot t+3} \, dt$

$s(t) = 2\int {t^{2}} \, dt - 30\int {t} \, dt +3\int \, dt$

$s(t) = \frac{2}{3}\cdot t^{3}-15\cdot t^{2}+3\cdot t +s_{o}$

If $t = 0$ and $s(0) = -5$ , then:

$-5 = \frac{2}{3}\cdot (0)^{3}-15\cdot (0)^{2}+3\cdot (0)+s_{o}$

$s_{o} = -5$

The displacement of the particle is given by $s(t) = \frac{2}{3}\cdot t^{3}-15\cdot t^{2}+3\cdot t -5$ , where $s$ is in meters and $t$ is in seconds.

7 0

3 years ago