Answer:
Explanation:
The change in electrical potential energy of a charged particle moving through a potential difference is given by
where
q is the magnitude of the charge of the particle
is the potential difference
In this problem:
- the charge of the particle is 3.00 elementary charges, so
- the potential difference is
So, the change in electrical potential energy is
Answer:
0.22 m
Explanation:
= Atmospheric pressure = 101325 Pa
= Pressure at the bottom = tex]2 P_{o}[/tex] = 2 (101325) = 202650 Pa
= height of the container = 7.59 m
= depth of the mercury
Pressure at the bottom = Atmospheric pressure + Pressure due to mercury + Pressure due to water
Density can be calculated using the following rule:
Density = mass/volume
We are given that:
mass = 41 grams
volume = 5 cm^3
Substitute with the givens in the above equation to get the density as follows:
Density = 41/5 = 8.2 g/cm^3
Based on the above calculations:
answer : 8.2
units : g/cm^3
Answer:
y₀ = 1020.3 m
Explanation:
This is a projectile launching exercise, in this case as the package is released its initial vertical velocity is zero.
y = y₀ + t - ½ g t²
when it reaches the ground its height is zero
0 = y₀ + 0 - ½ g t²
y₀ = ½ g t²
let's calculate
y₀ = ½ 9.8 14.43²
y₀ = 1020.3 m