Answer: 1.8
Explanation:
You are given
the object distance U = 24.8 cm
Focal length F = 16.0 cm
First find the image distance by using the formula:
1/f = 1/u + 1/v
Where V = image distance
Substitute u and f into the formula
1/16 = 1/24.8 + 1/v
1/ v = 1/16 - 1/24.8
1/v = 0.0625 - 0.04032258
1/v = 0.022177
Reciprocate both sides by dividing both sides by one
V = 45.09 cm
Magnification M is the ratio of image distance to the object distance. That is,
M = V/U
Substitute V and U into the formula
M = 45.09/24.8
M = 1.818
Magnification of the image is therefore equal to 1.8 approximately
Answer:
refractive index of plastic is 1.42
Explanation:
When light ray enters from one medium to other medium then due to transition of light it bends away or towards the normal, this phenomenon is known as refraction of light
So here we know that
here we have
now we have
For the first one 320
second
1200W
Data
R = 12 Ω ∆V = 120V I =? P =?
Solution:
According to Ohm’s law,
∆V = I R
I = ∆V / R
= 120 / 12
= 10 A
Power P = I ∆V
= 10 x 120
= 1200 W
Third
∆V = 120 V P = 60 W I =? R =?
Use the formula, P = I ∆V
I = P / ∆V = 60 / 120 = 0.5 A
∆V = I R
R = ∆V / I = 120 / 0.5 = 240 Ω
Answer:
In short, there are four types of natural silk produced around the world: Mulberry silk, Eri silk, Tasar silk and Muga silk. Mulberry silk contributes around as much as 90% of silk production, with the mulberry silkworm generally being regarded as the most important.
