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fredd [130]
3 years ago
12

Two moving objects collide and move apart on paths 90 degrees apart. The total momentum after the collision is _______ the total

momentum before the collision.
A. Equal to

B. Greater than

C. The momentum of the body is zero

D. The momentum of the body is increasing

Please help, thanks!
Physics
1 answer:
Tom [10]3 years ago
4 0
A is the correct answer
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Questions 15 out of 20
Olin [163]

Answer:

D

Explanation:

7 0
3 years ago
Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0
DENIUS [597]

Answer:

Tension in the string is equal to 58.33 N ( this will be the strength of the string )

Explanation:

We have given mass m = 1.7 kg

radius of the circle r = 0.48 mF=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N

Kinetic energy is given 14 J

Kinetic energy is equal to KE=\frac{1}{2}mv^2

So \frac{1}{2}\times 1.7\times v^2=14

v^2=16.47

v = 4.05 m/sec

Centripetal force is equal to F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N

So tension in the string will be equal to 58.33 N ( this will be the strength of the string )

3 0
3 years ago
A wooden log is displaced to a distance of 20m in 10 seconds by applying 500N effort . Calculate the workdone and power.​
nata0808 [166]

A wooden log is displaced to a distance of 20m in 10 seconds by applying 500N effort . Calculate the workdone and power...

Solution,

displacement = 20 m

time = 10 sec

force = 500 N

work done = ?

power = ?

Now ,

work done = f × s

= 500 N × 20 m

= 10000 j

Now ,

power \:  =  \frac{w}{t}  \\  =  \frac{10000j}{10sec}  \\   = 1000W

~nightmare 5474~

8 0
3 years ago
Read 2 more answers
Thermal conductivity of a material is given as 129Btuft–¹ h–¹°F–¹.Calculate this thermal conductivity in Jm–¹s–¹°C–¹(Given: 1Btu
ss7ja [257]

Answer:

223.25 $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$

Explanation:

The thermal conductivity of an object is defined as the measure or the ability of the object to transfer heat or conduct heat through its body.

In the context, the thermal conductivity of the material is given as

$=129 \text{ Btu ft}^{-1}\text{h}^{-1}^\circ\text{F}^{-1}$

And it is given that :

1 Btu = 1055 J

1 ft = 0.3048 m

$1^\circ F = \frac{5}{9}^\circ C$

We know that 1 h = 3600 s

So the thermal conductivity of the material in $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$ is  :

Thermal conductivity :

$=\frac{129 \text{ Btu}}{1 \text{ ft }\times \text{1 h}\times 1^\circ\text{F}}$

$=\frac{129 \times 1055 \text{ J}}{0.3048 \text{ m} \ \times 3600 \text{ s}\ \times \frac{5}{9}^\circ \text{C}}$

=  223.25 $\text{Jm}^{-1}\text{s}^{-1}^\circ\text{C}^{-1}$

3 0
3 years ago
In a simplified model of a hydrogen atom, the electron moves around the proton nucleus in a circular orbit of radius 0.53×10−10m
Ksenya-84 [330]

Answer

given,

radius of the circular orbit, r = 0.53 x 10⁻¹⁰ m

mass of electron, M = 9.11 x 10⁻³¹ Kg

charge of electron, q₁ = 1.6 x 10⁻¹⁹ C

                                q₂ = 1.6 x 10⁻¹⁹ C

we know, force between two charges

F = \dfrac{kq_1q_2}{r^2}

F = \dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.53\times 10^{-10})^2}

  F = 8.20 x 10⁻⁸ N

b) using newton's second law

F = m a

m a =  8.20 x 10⁻⁸

a =\dfrac{8.20\times 10^{-8}}{9.11\times 10^{-31}}

    a = 9 x 10²² m/s²

c) speed of the electron

 a =\dfrac{v^2}{r}

 9\times 10^{22} =\dfrac{v^2}{0.53\times 10^{-10}}

   v² = 4.77 x 10¹²

  v = 2.18 x 10⁶ m/s

d) the period of the circular motion.

    T=\dfrac{2\pi}{\omega}

    T=\dfrac{2\pi r}{v}

    T=\dfrac{2\pi\times 0.53\times 10^{-10}}{2.18\times 10^6}

          T = 1.53 x 10⁻¹⁶ s

8 0
3 years ago
Read 2 more answers
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