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solniwko [45]
3 years ago
13

What type of reaction is shown below?

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

Decomposition Reaction

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The melting point of H₂O(s) is 0 °C. Would you expect the melting point of H₂S(s) to be 85 °C, 0 °C or -85 °C.? Justify your cho
dimulka [17.4K]

Answer:

-85 °C

Explanation:

O and S are in the same group( Group 16). Since S is below O it's atomic mass is higher than O. So molar mass of H2S is higher than H2O. The strength of Vanderwaal Interactions ( London dispersion forces) increases when the molar mass increases. However, only H2O can form H bonds with each other. This is because electronegativity of O is higher than S and therefore H in H2O has a higher partial positive charge than H of H2S.

H bond dominate among these 2 types of forces so the strength of attractions between molecules is higher in H2O than H2S. Therefore more energy should be supplied for H2O to break inter

molecular forces and convert from solid to liquid state than H2S. So mpt of H2O must be higher than that of H2S.

5 0
3 years ago
Some students decide to plant their own garden. They want to eat a more plant-based diet For meat, they will buy locally from a
ozzi

Answer:

composting scraps

recycling is the action or process of converting waste into reusable material.

7 0
3 years ago
Lactose, C12H22O11, is a naturally occurring sugar found in mammalian milk. A 0.335 M solution of lactose in water has a density
Dmitry_Shevchenko [17]

The molality of the solution is 0.00037 m.

<h3>What is concentration?</h3>

The term concentration refers to the amount of solute in a solution.

We have the following information;

Molarity = 0.335 M

Density =  1.0432 g/mL

Temperature = 20 o C

The molality of the solution is obtained from;

m = 0.335 M ×  1.0432 g/mL/ 1000(1.0432 g/mL) - 0.335 M (342 g/mol)

m = 0.344/1043.2 - 114.57

m =  0.344/928.63

m = 0.00037 m

Learn more about molality of solution: brainly.com/question/4580605

5 0
3 years ago
How many liters of space will 7.80 moles of methane gas (CH4) occupy at STP
Alchen [17]

Answer:

V CH4(g) = 190.6 L

Explanation:

assuming ideal gas:

  • PV = RTn

∴ STP: T =298 K and P = 1 atm

∴ R = 0.082 atm.L/K.mol

∴ moles (n) = 7.80 mol CH4(g)

∴ Volume CH4(g) = ?

⇒ V = RTn/P

⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)

⇒ V CH4(g) = 190.6 L

4 0
4 years ago
During steps 6–8, the
Allushta [10]

Answer:

Particle Size

Reaction rate

3 0
3 years ago
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