Answer:
about 19 or 20 g
Explanation:
To do this, is neccesary to watch a solubility curve of this compound. This is the only way that you can know how many grams are neccesary to dissolve this compound in 50 mL of water to a given temperature.
Now, if you watched the attached graph, you can see the solubility curve of many compounds in 100 g of water (or 100 mL of water). So, to know how many do you need in 50 mL, it's just the half.
So watching the curve, you can see that at 20 °C, we simply need between 35 g and 40 g. Let's just say we need 38 grams of NH4Cl to be dissolved in 100 mL of water.
So, in 50 mL, it's just the half. So, we only need 19 g or 20 g of NH4Cl at 20 °C, to dissolve this compound in water.
Answer:
b
Explanation:
[H3O+] = 10-pH = 10-3.4 ≅ 3.981 x 10^-4 moles/liter
Answer:
1.31 X 10^ -10 joules per Fe 56 atom
Explanation:
The mass of a proton is 1.673 × 10-24 g. The mass of a neutron is 1.675 × 10-24 g. The mass of the nucleus of an 56Fe atom is 9.289 × 10-23 g. What is the nuclear binding energy (in J) for 56Fe? (c = 3.00 × 108 m/s)
some of the theoretical mass will be converted to binding energy
by Einstein's famous relativity equation
E = mc^2
where E is in joules, m is in Kgm. c is in m/sec
56Fe is element 26 so it has 26 protons and 56 -26 =30 neutrons
its theoretical nuclear mass is
(26 X 1.673 X 10^-24) + (30X1.675 X 10^-24) =
(43.498 X 10^-24) + (50.250 X 10^-24)=
93.748 X 10^24 gm
but its actual mass is 9.289 X 10^-23 g or
92.289 X 10^-24 g
the mas defect is the theoretical mass minus the actual
1.459 X 10^-24 gm =^
1.459 X 10^-27 Kgm
c = 3.00 X 10* m/s=
so joules of binding energy = (1.459 X 10^-27) X 9 X10^16)
1.31 X 10^ -10 joules per Fe 56 atom
Answer:
Option c
Explanation:
In the allene, 
Central atom forms two sigma bond and two pi bond.
Hybridization of central atom = sp
Hybridization of two terminal C = 
Allene is a nonplanar molecules. This is because of the planes of two
groups which are twisted 90 ° to each other.
Therefore, the two H atoms on one C lie above and below the plane defined by the other
group.
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