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alexandr1967 [171]
3 years ago
13

Convert 4.86 x 104g of Mg to moles.

Chemistry
2 answers:
maksim [4K]3 years ago
7 0

Answer : The moles of magnesium (Mg) is, 1.99\times 10^3moles

Solution : Given,

Mass of magnesium (Mg) = 4.86\times 10^4g

Molar mass of magnesium (Mg) = 24.31 g/mole

Formula used :

\text{Moles of Mg}=\frac{\text{Mass of Mg}}{\text{Molar mass of Mg}}=\frac{4.86\times 10^4g}{24.31g/mole}=1.99\times 10^3moles

Therefore, the moles of magnesium (Mg) is, 1.99\times 10^3moles

bazaltina [42]3 years ago
5 0

Explanation:

Number of moles equal to the given mass divided by molar mass of the element or compound.

Mathematically,       No. of moles = \frac{mass given}{Molar mass}

The given mass is 4.86 \times 10^{4} g and molar mass is 24.30 g/mol.

Therefore, calculate the number of moles as follows.

          No. of moles = \frac{mass given}{Molar mass}

                                = \frac{4.86 \times 10^{4} g}{24.30 g/mol}

                                = 0.2 \times 10^{4} mol

                                = 2 \times 10^{3} mol

or,                             = 2000 mol

Thus, we can conclude that  4.86 \times 10^{4} g of Mg has 2000 moles.

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put the contributions to the understanding of the atomic structure in order from most recent at the top to the earliest at the b
r-ruslan [8.4K]

Answer:

From Top to Bottom:

- Democritus coming up with the concept of an atom

- Dalton discovering that atoms are the smallest part of an element

- Rutherford discovering the nucleus of an atom

- Thomson discovering electrons

- Bohr modeling electrons orbiting the nucleus

- Schrodinger modeling electrons in the electron cloud

Explanation:

The best way to think about this is from the inside out. Democrats (who lived long before any of the other scientists mentioned) was the one who thought of the idea of the atom. - Therefore, this must be first because all other choices are elaborations on the idea that atoms exist. Next must be Dalton. Dalton saw atoms as "cannonballs" if you will; a solid mass. So then after that, Rutherford and his gold foil experiment (he discovered that some rays he shot through gold foil were deflected back; ie the existence of concentrated areas in an atom, ie the nucleus). Then we get into the information on electrons. We must start with discovery (Thomson). Heres where it gets complicated. Electrons don't <em>actually </em>orbit the nucleus, they exist in electron clouds. So it would be Bohr, who came up with the idea that electron exist outside the nucleus, then Schrodinger, who elaborated on Bohr's theory. Hope this helps!

Nat, Junior

Accel + AP Chem student

5 0
1 year ago
Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu
nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,  

Cu(s)+Pb^{2+}(aq)\rightarrow Cu^{2+}(aq)+Pb(s)

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

E^0_{[Pb^{2+}/Pb]}=-0.13V

E^0_{[Cu^{2+}/Cu]}=+0.34V

E^0_{cell}=E^0_{cathode}-E^0_{anode}

E^0_{cell}=E^0_{[Pb^{2+}/Pb]}-E^0_{[Cu^{2+}/Cu]}

E^0_{cell}=-0.13V-(0.34V)=-0.47V

Now we have to calculate the standard Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = -0.47 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times (-0.47))=+90710J/mole=+90.71kJ/mole\approx +91kJ/mole

Therefore, the standard Gibbs free energy is +91 kJ/mole

6 0
2 years ago
FORENSIC SCIENCE HELP
Annette [7]
That is correct c
Explanation
7 0
2 years ago
How many molecules are in 1kg of water
Mila [183]

Answer:

334.2× 10²³ molecules

Explanation:

Given data:

Mass of water = 1 Kg ( 1000 g )

Number of molecules = ?

Solution:

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 1000 g/ 18 g/mol

Number of moles = 55.5 mol

1 mole contain 6.022× 10²³ molecules

55.5 mol×6.022× 10²³ molecules

334.2× 10²³ molecules

8 0
3 years ago
After a 4.626g sample of silver oxide is heated, 4.306g of silver metal remains. What is the empirical formula of the compound?
saw5 [17]

Answer:

The empirical formula is Ag2O.

The empirical formula is Ag2O.Explanation:

The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.

The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.The ratio of atoms is the same as the ratio of moles. So our job is to calculate the molar ratio of Ag to 2O.

do the steps ...

To get this into an integer ratio, we divide both numbers by the smaller value.

From this point on, I like to summarize the calculations in a table.

ElementAgMass/gXMolesXllRatiomllIntegers

—————————————————−———mAgXXXm7.96Xm0.07377Xll2.00mmm2

mlOXXXXl0.59mm0.0369Xml1mmmml1

There are 2 mol of Ag for 1 mol of O.

3 0
2 years ago
Read 2 more answers
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