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alexandr1967 [171]
3 years ago
13

Convert 4.86 x 104g of Mg to moles.

Chemistry
2 answers:
maksim [4K]3 years ago
7 0

Answer : The moles of magnesium (Mg) is, 1.99\times 10^3moles

Solution : Given,

Mass of magnesium (Mg) = 4.86\times 10^4g

Molar mass of magnesium (Mg) = 24.31 g/mole

Formula used :

\text{Moles of Mg}=\frac{\text{Mass of Mg}}{\text{Molar mass of Mg}}=\frac{4.86\times 10^4g}{24.31g/mole}=1.99\times 10^3moles

Therefore, the moles of magnesium (Mg) is, 1.99\times 10^3moles

bazaltina [42]3 years ago
5 0

Explanation:

Number of moles equal to the given mass divided by molar mass of the element or compound.

Mathematically,       No. of moles = \frac{mass given}{Molar mass}

The given mass is 4.86 \times 10^{4} g and molar mass is 24.30 g/mol.

Therefore, calculate the number of moles as follows.

          No. of moles = \frac{mass given}{Molar mass}

                                = \frac{4.86 \times 10^{4} g}{24.30 g/mol}

                                = 0.2 \times 10^{4} mol

                                = 2 \times 10^{3} mol

or,                             = 2000 mol

Thus, we can conclude that  4.86 \times 10^{4} g of Mg has 2000 moles.

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If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
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Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

                            C   +   O₂    -------------> CO₂

                          1 mol    1 mol                  1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

           C               +                        O₂                     ------------->        CO                 1 mol (12 g/mol)                      1 mol (32 g/mol)                      1 mol (44 g/mol)

                   

              C   +   O₂    -------------> CO₂

            12 g       32 g                   44 g

So,

we come to know that 32 g of Oxygen combine with 12 g  of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

                32 g of  O₂ ≅ 12 g of  C

                  11 g of O₂  ≅  g of  C

by doing cross multiplication

           g of C = 12 g x 11 g / 32 g

           g of C = 132 g / 32 g

           g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

                     12 g of  C ≅ 44 g of CO₂

                     4.13 g of C ≅  g of  CO₂

by doing cross multiplication

                    g of  CO₂ = 44 g x 4.13 g / 12 g

                    g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

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