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mars1129 [50]
3 years ago
14

A 56 kg pole vaulter falls from rest from a height of 5.1 m onto a foam rubber pad. The pole vaulter comes to rest 0.29 s after

landing on the pad.
Required:
a. Calculate the athlete's velocity just before reaching the pad
b. Calculate the constant force exerted on the pole vaulter due to the collision
Physics
1 answer:
never [62]3 years ago
6 0

Answer:

b. calculate the constant force exerted on the pole vaulter due to the collision

mbgiclbxhkr and you can see the pole and you are not to be a great friend of the day and night sweets is my first day of your life and my friends is my friend

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A car (mass = 1200 kg) is traveling at 31.1 m/s when it collides head-on with a sport utility vehicle (mass = 2830 kg) traveling
IrinaVladis [17]

Answer:

13.18 m/s

Explanation:

Let the velocity of sports utility car is

-u as it is moving in opposite direction.

mc = 1200 kg, uc = 31.1 m/s

ms = 2830 kg, us = - u = ?

Using conservation of momentum

mc × uc + ms × us = 0

1200 × 31.1 - 2830 × u = 0

u = 13.18 m/s

4 0
3 years ago
Two charges (q1 = 3.8*10-6C, q2 = 3.2*10-6C) are separated by a distance of d = 3.25 m. Consider q1 to be located at the origin.
Sergio039 [100]

Answer:

The distance is 1.69 m.

Explanation:

Given that,

First charge q_{1}= 3.8\times10^{-6}\ C

Second charge q_{2}=3.2\times10^{-6}\ C

Distance = 3.25 m

We need to calculate the distance

Using formula of electric field

E_{1}=E_{2}

\dfrac{kq_{1}}{x^2}=\dfrac{kq_{2}}{(d-x)^2}

\dfrac{q_{1}}{q_{2}}=\dfrac{(x)^2}{(d-x)^2}

\sqrt{\dfrac{q_{1}}{q_{2}}}=\dfrac{x}{d-x}

x=(d-x)\times\sqrt{\dfrac{q_{1}}{q_{2}}}

Put the value into the formula

x=(3.25-x)\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x+x\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}

x=\dfrac{3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}}{(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})}

x=1.69\ m

Hence, The distance is 1.69 m.

5 0
3 years ago
The force diagram shown here describes the forces that external objects (the surface andEarth) exert on a woman (in this scenari
sveticcg [70]

The three different motions are;

  • The upward motion of the woman is constant
  • The downward motion of the woman is also constant
  • The horizontal motion of the woman is zero.

<h3>What is force diagram?</h3>

Force diagram is a pictorial or graphical illustration of different forces acting on object.

In this given question, there two forces acting on the woman as depicted in the force diagram.

  • The first force is surface force (Fs)
  • The second force is force of Earth (FE)

In the given force diagram, the woman is in equilibrium, this implies that the surface force and the Earth force are equal.

The three different types of motion of the woman that are consistent with the force diagram include the following;

  • The upward motion of the woman is constant
  • The downward motion of the woman is also constant
  • The horizontal motion of the woman is zero since there is no horizontal force on the woman.

Learn more about force diagram here: brainly.com/question/3624253

#SPJ1

4 0
1 year ago
Question 3. AP PHYSICS. Currently learning about torque so I assume you apply torque. I don't get it at all
8090 [49]

wow that is confusing


8 0
3 years ago
A heating element has a resistance of 180 Ω and draws a current of 1.60 A. What is its power?
iragen [17]

its either 288Watts or 112.5 Watts

5 0
3 years ago
Read 2 more answers
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