A student uses a meter to measure 120 coulombs flowing through a circuit in 60 seconds. The electric current in this circuit will be 2 A
Current is a flow of electrical charge carriers, usually electrons or electron-deficient atoms. The common symbol for current is the uppercase letter I. The standard unit is the ampere, symbolized by A.
current = charge / time
given
time = 60 seconds
charge = 120 Coulombs
current = Q / T = 120 / 60 = 2 A
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The gravitational force between the spheres is
where <em>G</em> = 6.674 x 10⁻¹¹ N m²/kg².
The weight of the lighter sphere is
where <em>g</em> = 9.80 m/s².
The ratio between the two forces is then
Ok so basically I’m here for the points cuz I gotta quiz do in 10 minutes sorry
solution:
radius of steel ball(r)=5cm=0.05m
density of ball =8000kgm
terminal velocity(v)=25m/s^2
density of air( d) =1.29 kgm
now
volume of ball(V)=4/3pir^3=1.33×3.14×0.05^3=0.00052 m^3
density of ball= mass of ball/Volume of ball
or, 8000=m/0.00052
or, m=4.16 kg
weight of the ball (W)= mg=4.16×10=41.6 N
viscous force(F)=6 × pi × eta × r × v
=6×3.14×eta×0.05×25
=23.55×eta
To attain the terminal velocity,
Fiscous force=Weight
or, 23.55× eta = 41.6
or, eta = 1.76
whete eta is the coefficient of viscosity.
Lets se
And
So
If spring constant is doubled mass must be doubled
