Answer:
The mass of solution the student should use is 23.4 g.
Explanation:
Hi there!
The concentration of the solution, 42.7% w/w, indicates that there is 42.7 g of isopropenylbenzene (IPB) per 100 g of solution. Then, if the student needs 10.00 g IPB, the mass of solution the student should take will be:
10.00 g IPB · (100 g solution/42.7 g IPB) = 23.4 g solution.
Then, the mass of solution the student should use is 23.4 g.
Heat energy released : 167.2 kJ
<h3>Further explanation</h3>
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
m = 2000 g
c = 4.18 J/ g ° C
∆t = 20 ° C

Answer:
Sound waves are formed when a vibrating object causes the surrounding medium to vibrate. A medium is a material (solid, liquid or gas) which a wave travels through. As sound waves move through a medium the particles vibrate forwards and backwards. ... So the nearer you are to a sound the louder it sounds to us.
Thank you for posting your question here at brainly. Below is the answer:
At 25 C and 1 atm pressure (the standard state): P is a solid, O2 is a gas, and Cl2 is a gas.
<span>P(s) + O2(g) + Cl2(g) ==> POCl3(l) </span>
<span>To make 1 mole of POCl3, we need to start with 1 mole of P, 1/2 mole of O2, and 3/2 mole of Cl2. </span>
<span>P(s) + 1/2O2(g) + 3/2Cl2(g) ==> POCl3(l) </span>
<span>NOTE: Some people write P as P4(s), in which case you would need 1/4 mole P4.</span>
Answer:
0.928 M
Explanation:
The concentration of acid can be determined by using the volume used and the concentration and volume used of base.
We will use the law of equivalence of moles.
M₁V₁=M₂V₂
M₁ = concentration of base used
V₁ = volume of base used
M₂ = concentration of acid used =? (to be determined)
V₂ = volume of acid used
The initial concentration of KOH used is diluted so let us find the final concentration of KOH after dilution
initial moles = final moles
initial concentration X initial volume = final concentration X final volume
6.2 X 2.1 = 250 X final concentration
final concentration = 0.052 M = M₁
V₁ = 36.9 mL
V₂ = 6.2 mL
Here with each mole of phosphoric acid three moles of KOH are used.
Therefore
3 M₁V₁ = M₂V₂
M₂ = 