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Rudiy27
3 years ago
12

0.254g lead(ii)ethanoate, on adding excess K2CrO4 solution, gave 0.130g of lead(ii)chromate precipitate. what is the percentage

composition of Pb in the organic salt? (O = 16, Cr = 52, Pb = 207).​
Chemistry
1 answer:
Alborosie3 years ago
3 0

Answer:

32.8%

Explanation:

All of the Pb⁺² species precipitated as lead(II) cromate, PbCrO₄ (we know this as excess K₂CrO₄ was used).

First we convert 0.130 g of PbCrO₄ into moles, using its molar mass:

  • 0.130 g ÷ 323 g/mol = 4.02x10⁻⁴ mol PbCrO₄

There's 1 Pb⁺² mol per PbCrO₄ mol, so in total 4.02x10⁻⁴ moles of Pb⁺² were in the ethanoate sample.

We <u>convert those 4.02x10⁻⁴ moles of Pb into grams</u>:

  • 4.02x10⁻⁴ mol * 207 g/mol = 0.083 g Pb

Finally we calculate the percentage composition of Pb:

  • 0.083 g Pb / 0.254 g salt * 100% = 32.8%
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A mixture of hept-1-yne, hept-2-yne, and hept-3-yne was hydrogenated in the presence of a platinum catalyst until hydrogen uptak
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Answer:

Only one seven carbon hydrocarbon was produced.

Explanation:

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3 years ago
If 90.0 grams of ethane reacted with excess chlorine,how many grams of dicarbon hexachloride would form
tigry1 [53]

Answer:

709 g  

Step-by-step explanation:

a) Balanced equation

Normally, we would need a balanced chemical equation.

However, we can get by with a partial equation, as log as carbon atoms are balanced.

We know we will need an equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.  

M_r:    30.07          236.74

           C₂H₆ + … ⟶ C₂Cl₆ + …  

m/g:    90.0

(i) Calculate the moles of C₂H₆

n = 90.0 g C₂H₆  × (1 mol C₂H₆ /30.07 g C₂H₆)

  = 2.993 mol C₂H₆

(ii) Calculate the moles of C₂Cl₆

The molar ratio is (1 mol C₂Cl₆/1 mol C₂H₆)

n = 2.993 mol C₂H₆ × (1 mol C₂Cl₆/1 mol C₂H₆)

  = 2.993 mol C₂Cl₆

(iii) Calculate the mass of C₂Cl₆

m = 2.993 mol C₂Cl₆ × (236.74 g C₂Cl₆/1 mol C₂Cl₆)

m = 709 g C₂Cl₆

The reaction produces 709 g C₂Cl₆.

6 0
3 years ago
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Anni [7]
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5 0
3 years ago
How many moles of aluminum oxide will be formed from 17 moles of aluminum reaction?
Ainat [17]

Answer:

8.5 moles of Al₂O₃ will formed

Explanation:

Given data:

Number of moles of Al = 17 mol

Number of moles of Al₂O₃ formed = ?

Solution:

Chemical equation:

4Al  +  3O₂     →     2Al₂O₃

Now we will compare the moles of Al₂O₃  with Al.

                  Al            :            Al₂O₃      

                   4            :              2

                   17           :            2/4×17 = 8.5 mol

8.5 moles of Al₂O₃ will formed.    

7 0
3 years ago
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