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MissTica
3 years ago
9

Atsuko Jackson when was her show and who made her?

Physics
1 answer:
NeX [460]3 years ago
4 0

Answer:

Atsuko Jackson is a fictional character from the anime television series Michiko to Hatchin. She is a police women her show used to airs on Mondays to my knowledge it was from 2008 to 2009 from my search.

Explanation:

Atsuko Jackson

Atsuko Jackson is a fictional character from the anime television series Michiko to Hatchin.

Played by: Maki Sakai

TV shows: Michiko to Hatchin (2008 - 2009)

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If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed? (e = 1.60 × 10-19
Nata [24]

Answer:

So speed of electron will be 5.89\times 10^{-7}m/sec

Explanation:

We have given potential difference V = 9.9 KV

Charge on electron e=1.6\times 10^{-19}

So energy of electron E=eV=1.6\times 10^{-19}\times 9.9\times 10^3=15.84\times 10^{-16}J

This energy of electron will be equal to kinetic energy of electron

So \frac{1}{2}mv^2=15.84\times 10^{-16}J

\frac{1}{2}\times 9.11\times 10^{-31}v^2=15.84\times 10^{-16}

v=5.89\times 10^{-7}m/sec

So speed of electron will be 5.89\times 10^{-7}m/sec

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What would MOST LIKELY happen if the amount of incoming solar energy decreased without a change in the amount of reflection or o
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3 years ago
Read 2 more answers
1. How much power does a light bulb contain if it does 600J of work in 5 seconds?
dimaraw [331]

Answer:

120 watts

Explanation:

#1: 120 watts

#2: 667 watts

#3: 3 watts

#4: i forgot how to do this one

5 0
3 years ago
Which statements accurately describe mechanical waves​
AleksAgata [21]

Answer:

Explanation:

so a mechanical wave transfers energy through a medium but unlike other waves that move through very long distances

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3 years ago
Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to
stiks02 [169]

Now, there is some information missing to this problem, since generally you will be given a figure to analyze like the one on the attached picture. The whole problem should look something like this:

"Beam AB has a negligible mass and thickness, and supports the 200kg uniform block. It is pinned at A and rests on the top of a post, having a mass of 20 kg and negligible thickness. Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to 360 N , the post slips at both B and C simultaneously."

Answer:

\mu_{sB}=0.126

\mu_{sC}=0.168

Explanation:

In order to solve this problem we will need to draw a free body diagram of each of the components of the system (see attached pictures) and analyze each of them. Let's take the free body diagram of the beam, so when analyzing it we get:

Sum of torques:

\sum \tau_{A}=0

N(3m)-W(1.5m)=0

When solving for N we get:

N=\frac{W(1.5m)}{3m}

N=\frac{(1962N)(1.5m)}{3m}

N=981N

Now we can analyze the column. In this case we need to take into account that there will be no P-ycomponent affecting the beam since it's a slider and we'll assume there is no friction between the slider and the column. So when analyzing the column we get the following:

First, the forces in y.

\sum F_{y}=0

-F_{By}+N_{c}=0

F_{By}=N_{c}

Next, the forces in x.

\sum F_{x}=0

-f_{sB}-f_{sC}+P_{x}=0

We can find the x-component of force P like this:

P_{x}=360N(\frac{4}{5})=288N

and finally the torques about C.

\sum \tau_{C}=0

f_{sB}(1.75m)-P_{x}(0.75m)=0

f_{sB}=\frac{288N(0.75m)}{1.75m}

f_{sB}=123.43N

With the static friction force in point B we can find the coefficient of static friction in B:

\mu_{sB}=\frac{f_{sB}}{N}

\mu_{sB}=\frac{123.43N}{981N}

\mu_{sB}=0.126

And now we can find the friction force in C.

f_{sC}=P_{x}-f_{xB}

f_{sC}=288N-123.43N=164.57N

f_{sC}=N_{c}\mu_{sC}

and now we can use this to find static friction coefficient in point C.

\mu_{sC}=\frac{f_{sC}}{N}

\mu_{sC}=\frac{164.57N}{981N}

\mu_{sB}=0.168

3 0
3 years ago
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