<span>Law of Conservation of Energy states that the total amount of energy remains constant in an isolated system and Energy can be neither created nor destroyed.
</span>
Therefore,
<span>The refrigerator</span><span> removed 272 Joules of energy from the food (making it colder) and dumped 272 J of energy outside (heat of the refrigerator).</span>
Parfocal is the term used to describe a microscope that maintains focus when the objective lenses are replaced.
<h3>
What is the name of the objective lens ?</h3>
For observing minute features within a specimen sample, a high-powered objective lens, often known as a "high dry" lens, is perfect. You can see a very detailed image of the specimen on your slide thanks to the 400x total magnification that a high-power objective lens and a 10x eyepiece provide.
The four objective lenses on your microscope are for scanning (4x), low (10x), high (40x), and oil immersion (100x).
The first-stage lens used to create a picture from electrons leaving the specimen is referred to as the "objective lens." The objective lens is the most crucial component of the imaging system since the quality of the images is determined by how well it performs (resolution, contrast, etc.,).
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Answer:
F = 2.668*10_-6[N]
Explanation:
We can calculate this force using the law of universal gravitation raised by Isaac Newton
![m_{t}=20000[kg]\\m_{c}= 200[kg]\\r = 10[m]\\G = 6.67*10^{-11}[\frac{N*m^{2} }{kg} ] \\](https://tex.z-dn.net/?f=m_%7Bt%7D%3D20000%5Bkg%5D%5C%5Cm_%7Bc%7D%3D%20200%5Bkg%5D%5C%5Cr%20%3D%2010%5Bm%5D%5C%5CG%20%3D%206.67%2A10%5E%7B-11%7D%5B%5Cfrac%7BN%2Am%5E%7B2%7D%20%7D%7Bkg%7D%20%5D%20%5C%5C)
And the force is given by the following expression:
![F=G*\frac{m_{t}*m_{c}}{r^{2} } \\F=6.67*10^{-11} *\frac{20000*200}{10^{2} }\\F=2.668*10^{-6} [N]](https://tex.z-dn.net/?f=F%3DG%2A%5Cfrac%7Bm_%7Bt%7D%2Am_%7Bc%7D%7D%7Br%5E%7B2%7D%20%7D%20%5C%5CF%3D6.67%2A10%5E%7B-11%7D%20%2A%5Cfrac%7B20000%2A200%7D%7B10%5E%7B2%7D%20%7D%5C%5CF%3D2.668%2A10%5E%7B-6%7D%20%5BN%5D)
Answer:
a) 17 N
b) 21 N
Explanation:
At the 3 o'clock position, the sum of the forces towards the center is:
∑F = ma
T = m v² / r
19 = m v² / r
At the 12 o'clock position, the sum of the forces towards the center is:
∑F = ma
T + mg = m v² / r
T + (0.18)(9.8) = 19
T = 17.2 N
At the 6 o'clock position, the sum of the forces towards the center is:
∑F = ma
T − mg = m v² / r
T − (0.18)(9.8) = 19
T = 20.8 N
Rounding to two significant figures, the tensions are 17 N and 21 N.
Answer:
D
Explanation: Hope this helps Sorry if it dosent
