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3 years ago

A car accelerates at a rate of 4 m/s in 5 s. Calculate the change of velocity PLS HELP

Physics

1 answer:

garri49 [273]3 years ago

6 0

Answer:

Explanation:

a=Δv/Δt

Δv=a*Δt

a=4 m/s2

t=5 s

Δv=4*5

Δv=20 m/s

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3 years ago

List the following items in order of decreasing speed, from greatest to least: (i) A wind-up toy car that moves 0.15 m in 2.5 s.

a_sh-v [17]

Answer:

(iii) > (ii) > (iv) > (i)

Explanation:

Part (i):

$\textrm{Speed of the wind-up toy} = \dfrac{\textrm{distance traveled}}{\textrm{Time taken}}\\\Rightarrow v_1=\dfrac{0.15\ m}{2.5\ s}\\\Rightarrow v_1 = 0.06\ m/s$

Part (ii):

$\textrm{Speed of the soccer ball} = \dfrac{\textrm{distance traveled}}{\textrm{Time taken}}\\\Rightarrow v_2=\dfrac{2.3\ m}{0.55\ s}\\\Rightarrow v_2 = 4.18\ m/s$

Part (iii):

$\textrm{Speed of the bicycle} = \dfrac{\textrm{distance traveled}}{\textrm{Time taken}}\\\Rightarrow v_3=\dfrac{0.66\ m}{0.075\ s}\\\Rightarrow v_3 = 8.8\ m/s$

Part (iv):

$\textrm{Speed of the cat} = \dfrac{\textrm{distance traveled}}{\textrm{Time taken}}\\\Rightarrow v_4=\dfrac{8.0\ m}{2.0\ s}\\\Rightarrow v_4 = 4.0\ m/s$

From the above calculations, we have

$v_3>v_2>v_4>v_1$

So, the speed in the parts mentioned arranged in decreasing order as follow:

(iii) > (ii) > (iv) > (i)

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2 years ago