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The distance of the galaxy is 32.86 Mpc.
Using the hubble law, v = H₀D where v = apparent velocity of galaxy = 2300 km/s, H = hubble constant = 70 km/s/Mpc and D = distance of galaxy.
Since we require the distance of the galaxy, we make D subject of the formula in the equation. So, we have
D = v/H₀
Substituting the values of the variables into the equation, we have
D = 2300 km/s ÷ 70 km/s/Mpc
D = 32.86 Mpc
So, the distance of the galaxy is 32.86 Mpc
Learn more about hubble law here:
brainly.com/question/18484687
It’s a total of 16 cm because it starts at 0 moves then moves to left then the right then the left
We can substitute the given values into the equation for T, given the surrounding temperature T0 = 0, initial temperature T1 = 140, constant k = -0.0815, and time t = 15 minutes.
T = 0 + (140 - 0)e^(-0.0815*15) = 140e^(-1.2225) = 41.23°F
Answer: A (
,309.8°)
B (2
, 315°)
C (
, 26.56°)
Explanation: To transform rectangular coordinates into polar coordinates use:
and 
For point A:




°
Point A is in the II quadrant, so we substract the angle for 360° since it is in degrees:

309.8°
Polar coordinates for point A is (
, 309.8°)
For point B:





°
Point B is in IV quadrant, so:

315°
Polar coordinates for point B is (
, 315°)
For point C:





26.56°
Polar coordinates for point C is (
, 26.56°)